資源簡介
實驗一 算術邏輯單元
１. 實驗目的
(1) 掌握運算器的工作原理。
(2) 驗證運算器的功能
２. 實驗要求
(1)基本要求
設計一個4位的算術邏輯單元，滿足以下要求。
①4位算術邏輯單元能夠進行下列運算：加法、減法、加1、減1、與、或、非和傳遞。用3位操作碼進行運算，控制方式如下表所示。
運算操作碼 運 算 對標識位Z和C的影響
000 result ←A+B 影響標志位Z和C
001 result ←A+1 影響標志位Z和C
010 result ←A-B 影響標志位Z和C
011 result ←A-1 影響標志位Z和C
100 result←A and B 影響標志位Z
代碼片段和文件信息
?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????文件???????2860??2010-11-14?06:10??sy1\db\logic_util_heursitic.dat
?????文件???????2530??2010-10-27?23:32??sy1\db\mux_5oc.tdf
?????文件???????2176??2010-11-14?06:10??sy1\db\prev_cmp_YSQ.asm.qmsg
?????文件??????33583??2010-11-14?06:10??sy1\db\prev_cmp_YSQ.fit.qmsg
?????文件???????3314??2010-11-14?06:10??sy1\db\prev_cmp_YSQ.map.qmsg
?????文件???????7239??2010-11-14?06:11??sy1\db\prev_cmp_YSQ.qmsg
?????文件???????2315??2010-11-14?06:11??sy1\db\prev_cmp_YSQ.sim.qmsg
?????文件??????37109??2010-11-14?06:10??sy1\db\prev_cmp_YSQ.tan.qmsg
?????文件???????8186??2010-11-14?06:11??sy1\db\wed.wsf
?????文件???????3881??2010-11-03?23:13??sy1\db\YSQ.（0）.cnf.cdb
?????文件???????1250??2010-11-03?23:13??sy1\db\YSQ.（0）.cnf.hdb
?????文件???????2176??2010-11-14?06:10??sy1\db\YSQ.asm.qmsg
?????文件???????1438??2010-11-14?06:10??sy1\db\YSQ.asm.rdb
?????文件???????6795??2010-11-14?06:10??sy1\db\YSQ.asm_labs.ddb
?????文件????????500??2010-11-14?06:11??sy1\db\YSQ.cbx.xml
?????文件????????601??2010-11-14?06:10??sy1\db\YSQ.cmp.bpm
?????文件??????12040??2010-11-14?06:10??sy1\db\YSQ.cmp.cdb
?????文件?????????28??2010-11-14?06:10??sy1\db\YSQ.cmp.ecobp
?????文件???????9454??2010-11-14?06:10??sy1\db\YSQ.cmp.hdb
?????文件????????196??2010-11-14?06:10??sy1\db\YSQ.cmp.kpt
?????文件??????14409??2010-11-14?06:10??sy1\db\YSQ.cmp.logdb
?????文件??????23775??2010-11-14?06:10??sy1\db\YSQ.cmp.rdb
?????文件???????9617??2010-11-14?06:10??sy1\db\YSQ.cmp.tdb
?????文件?????118518??2010-11-14?06:10??sy1\db\YSQ.cmp0.ddb
?????文件????????201??2010-11-14?06:10??sy1\db\YSQ.cmp_merge.kpt
?????文件????????136??2010-10-27?23:26??sy1\db\YSQ.db_info
?????文件????????160??2010-11-14?06:11??sy1\db\YSQ.eco.cdb
?????文件??????????3??2010-11-14?06:11??sy1\db\YSQ.eds_overflow
?????文件??????33583??2010-11-14?06:10??sy1\db\YSQ.fit.qmsg
?????文件???????4990??2010-11-14?06:11??sy1\db\YSQ.fnsim.cdb
............此處省略73個文件信息
-----------?---------??----------?-----??----
?????文件???????2860??2010-11-14?06:10??sy1\db\logic_util_heursitic.dat
?????文件???????2530??2010-10-27?23:32??sy1\db\mux_5oc.tdf
?????文件???????2176??2010-11-14?06:10??sy1\db\prev_cmp_YSQ.asm.qmsg
?????文件??????33583??2010-11-14?06:10??sy1\db\prev_cmp_YSQ.fit.qmsg
?????文件???????3314??2010-11-14?06:10??sy1\db\prev_cmp_YSQ.map.qmsg
?????文件???????7239??2010-11-14?06:11??sy1\db\prev_cmp_YSQ.qmsg
?????文件???????2315??2010-11-14?06:11??sy1\db\prev_cmp_YSQ.sim.qmsg
?????文件??????37109??2010-11-14?06:10??sy1\db\prev_cmp_YSQ.tan.qmsg
?????文件???????8186??2010-11-14?06:11??sy1\db\wed.wsf
?????文件???????3881??2010-11-03?23:13??sy1\db\YSQ.（0）.cnf.cdb
?????文件???????1250??2010-11-03?23:13??sy1\db\YSQ.（0）.cnf.hdb
?????文件???????2176??2010-11-14?06:10??sy1\db\YSQ.asm.qmsg
?????文件???????1438??2010-11-14?06:10??sy1\db\YSQ.asm.rdb
?????文件???????6795??2010-11-14?06:10??sy1\db\YSQ.asm_labs.ddb
?????文件????????500??2010-11-14?06:11??sy1\db\YSQ.cbx.xm
?????文件????????601??2010-11-14?06:10??sy1\db\YSQ.cmp.bpm
?????文件??????12040??2010-11-14?06:10??sy1\db\YSQ.cmp.cdb
?????文件?????????28??2010-11-14?06:10??sy1\db\YSQ.cmp.ecobp
?????文件???????9454??2010-11-14?06:10??sy1\db\YSQ.cmp.hdb
?????文件????????196??2010-11-14?06:10??sy1\db\YSQ.cmp.kpt
?????文件??????14409??2010-11-14?06:10??sy1\db\YSQ.cmp.logdb
?????文件??????23775??2010-11-14?06:10??sy1\db\YSQ.cmp.rdb
?????文件???????9617??2010-11-14?06:10??sy1\db\YSQ.cmp.tdb
?????文件?????118518??2010-11-14?06:10??sy1\db\YSQ.cmp0.ddb
?????文件????????201??2010-11-14?06:10??sy1\db\YSQ.cmp_merge.kpt
?????文件????????136??2010-10-27?23:26??sy1\db\YSQ.db_info
?????文件????????160??2010-11-14?06:11??sy1\db\YSQ.eco.cdb
?????文件??????????3??2010-11-14?06:11??sy1\db\YSQ.eds_overflow
?????文件??????33583??2010-11-14?06:10??sy1\db\YSQ.fit.qmsg
?????文件???????4990??2010-11-14?06:11??sy1\db\YSQ.fnsim.cdb
............此處省略73個文件信息
- 上一篇：JCL題目大全，很全的資料。
- 下一篇：個人信息管理系統的設計與實現
評論
共有 條評論