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  • 大小: 11.96MB
    文件類型: .zip
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    發布日期: 2023-07-12
  • 語言: 其他
  • 標簽: 并行??openmp??

資源簡介

機械工業出版社 并行程序設計導論 第五章練習題5.6自己寫來練手的。

資源截圖

代碼片段和文件信息 


#include?“stdafx.h“
#include?
#include?
#include??
#include?
#include
#include
#include
#include??
#include?
#include???
using?namespace?std;
#define?Nr??5
int?main（）{
	queue?d;
	
	//string?*d=new?string[Nr];
	/*for（int?i=0;i	{
		d[i]=““;
	}*/
	//信號燈
	int?empty=5;//隊列中的空閑空間大小
	int?full=0;//隊列中已使用空間的大小

????int?nthreads;
	int?tiditip;
	int?first;
	omp_lock_t?lockP;
	//當前生產者的數目
	int?numberOfProductor=0;
	//初始化鎖
	omp_init_lock（&lockP）;
	//線程總數目為4
	omp_set_num_threads（4）;
	first=1;
	//omp_in_parallel（）;
	//omp_set_dynamic（20）;
	

#pragma?omp?parallel??shared（demptyfullnumberOfProductor）?private（tiditip）?firstprivate（first）?
{
		if（first==1）
		{
			tid=omp_get_thread_num（）;
			first=0;			
			nthreads?=?omp_get_num_threads（）;
			printf（“Number?of?threads?=?%d\n“?nthreads）;	
			printf（“Thread?%d?starting...\n“?tid）;
			tip=?tid?%?2;
		}
		//偶數線程為生產者
		if（tip==0）
		{???//?producator
			??//omp_set_lock（&lockP）;
					stringstream?strStream;??
					strStream?<					string?fileName;
					string?directPath;
					?char???buffer[MAX_PATH];???
????????????????????getcwd（buffer?MAX_PATH）;???
				??directPath=buffer;
				??fileName=directPath+“\\“+strStream.str（）+“.txt“;
				?//fileName=strStream.str（）+“.txt“;
					ifstream?fin（fileName）;
					while（!fin.eof（））
					{
						if（empty>0）
						{
						
							
					????????#pragma?omp?critical
					???????{
							????printf（“線程?%d?生產者?\n“tid）;
							printf（“生產者產生的數據為：“）;
							???string?str;
							???getline（finstr）?;
							???d.push（str）;
							???cout<						???????empty--;
							???full++;
					????????}
						}
						else
						{
							Sleep（1000）;
						}
					}				
				printf（“線程?%d退出！\n“tid）;
				#pragma?omp?critical
				{
					numberOfProductor++;
				?}
				?//omp_unset_lock（&lockP）;??			
		}
		?else//奇數線程為消費者
		{?
			??//omp_set_lock（&lockP）;
				????//?consumator
				???while（true）
				???{
					???if（numberOfProductor==2&&d.empty（））
					???{
						???break;
					??}
					???if（full>0&&!d.empty（））
					???{
					#pragma?omp?critical
					{
						printf（“線程?%d?消費者\n“tid）;
						char?sentences[255];
						string?str;
						str=d.front（）;
						//d.pop（）;
						str.copy（sentencesstr.length（）0）;?
						sentences[str.length（）?+?1]?=?‘\0‘;
						char?*tokenPtr=strtok（sentences“?“）;
						printf（“消費者分詞后的數據為：\n“）;
						while（tokenPtr!=NULL）
						{
							?cout<							?tokenPtr=strtok（NULL“?“）;
						}
						full--;
						empty++;
					}

						
					???}
					???else
					???{
						???Sleep（100）;
					???}
				???}
				??
		?}
?//omp_unset_lock（&lockP）;??
	//}
}

??
char?end=getch（）;
}



?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????目錄???????????0??2014-06-10?10:36??并行openmp程序生產者消費者-渠澗濤-104753130775\
?????目錄???????????0??2014-06-10?10:36??并行openmp程序生產者消費者-渠澗濤-104753130775\OpenMPP-C\
?????目錄???????????0??2014-06-10?10:36??并行openmp程序生產者消費者-渠澗濤-104753130775\OpenMPP-C\Debug\
?????文件?????????246??2014-06-09?20:41??并行openmp程序生產者消費者-渠澗濤-104753130775\OpenMPP-C\Debug\1.txt
?????文件?????????143??2014-06-09?20:41??并行openmp程序生產者消費者-渠澗濤-104753130775\OpenMPP-C\Debug\2.txt
?????文件?????????172??2014-06-09?20:41??并行openmp程序生產者消費者-渠澗濤-104753130775\OpenMPP-C\Debug\3.txt
?????文件?????????148??2014-06-09?20:41??并行openmp程序生產者消費者-渠澗濤-104753130775\OpenMPP-C\Debug\4.txt
?????文件??????122368??2014-06-10?10:33??并行openmp程序生產者消費者-渠澗濤-104753130775\OpenMPP-C\Debug\OpenMPP-C.exe
?????文件?????1069528??2014-06-10?10:33??并行openmp程序生產者消費者-渠澗濤-104753130775\OpenMPP-C\Debug\OpenMPP-C.ilk
?????文件?????1559552??2014-06-10?10:33??并行openmp程序生產者消費者-渠澗濤-104753130775\OpenMPP-C\Debug\OpenMPP-C.pdb
?????目錄???????????0??2014-06-10?10:36??并行openmp程序生產者消費者-渠澗濤-104753130775\OpenMPP-C\ipch\
?????目錄???????????0??2014-06-10?10:36??并行openmp程序生產者消費者-渠澗濤-104753130775\OpenMPP-C\ipch\openmpp-c-cd764e05\
?????文件?????2359296??2014-06-10?10:32??并行openmp程序生產者消費者-渠澗濤-104753130775\OpenMPP-C\ipch\openmpp-c-cd764e05\openmpp-c-eb288db.ipch
?????目錄???????????0??2014-06-10?10:36??并行openmp程序生產者消費者-渠澗濤-104753130775\OpenMPP-C\OpenMPP-C\
?????文件????33116160??2014-06-10?10:33??并行openmp程序生產者消費者-渠澗濤-104753130775\OpenMPP-C\OpenMPP-C.sdf
?????文件?????????894??2014-06-09?20:41??并行openmp程序生產者消費者-渠澗濤-104753130775\OpenMPP-C\OpenMPP-C.sln
?????文件???????18944??2014-06-10?10:33??并行openmp程序生產者消費者-渠澗濤-104753130775\OpenMPP-C\OpenMPP-C.suo
?????文件?????????216??2014-06-10?10:18??并行openmp程序生產者消費者-渠澗濤-104753130775\OpenMPP-C\OpenMPP-C\0.txt
?????文件?????????131??2014-06-10?10:17??并行openmp程序生產者消費者-渠澗濤-104753130775\OpenMPP-C\OpenMPP-C\2.txt
?????目錄???????????0??2014-06-10?10:36??并行openmp程序生產者消費者-渠澗濤-104753130775\OpenMPP-C\OpenMPP-C\Debug\
?????文件?????????246??2014-06-09?20:41??并行openmp程序生產者消費者-渠澗濤-104753130775\OpenMPP-C\OpenMPP-C\Debug\1.txt
?????文件?????????143??2014-06-09?20:41??并行openmp程序生產者消費者-渠澗濤-104753130775\OpenMPP-C\OpenMPP-C\Debug\2.txt
?????文件?????????172??2014-06-09?20:41??并行openmp程序生產者消費者-渠澗濤-104753130775\OpenMPP-C\OpenMPP-C\Debug\3.txt
?????文件?????????148??2014-06-09?20:41??并行openmp程序生產者消費者-渠澗濤-104753130775\OpenMPP-C\OpenMPP-C\Debug\4.txt
?????文件????????3050??2014-06-10?10:33??并行openmp程序生產者消費者-渠澗濤-104753130775\OpenMPP-C\OpenMPP-C\Debug\cl.command.1.tlog
?????文件???????37912??2014-06-10?10:33??并行openmp程序生產者消費者-渠澗濤-104753130775\OpenMPP-C\OpenMPP-C\Debug\CL.read.1.tlog
?????文件????????1684??2014-06-10?10:33??并行openmp程序生產者消費者-渠澗濤-104753130775\OpenMPP-C\OpenMPP-C\Debug\CL.write.1.tlog
?????文件???????????2??2014-06-10?10:33??并行openmp程序生產者消費者-渠澗濤-104753130775\OpenMPP-C\OpenMPP-C\Debug\link-cvtres.read.1.tlog
?????文件???????????2??2014-06-10?10:33??并行openmp程序生產者消費者-渠澗濤-104753130775\OpenMPP-C\OpenMPP-C\Debug\link-cvtres.write.1.tlog
?????文件???????????2??2014-06-10?10:33??并行openmp程序生產者消費者-渠澗濤-104753130775\OpenMPP-C\OpenMPP-C\Debug\link.11312-cvtres.read.1.tlog
?????文件???????????2??2014-06-10?10:33??并行openmp程序生產者消費者-渠澗濤-104753130775\OpenMPP-C\OpenMPP-C\Debug\link.11312-cvtres.write.1.tlog
............此處省略33個文件信息

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