%該程序用于讀取原始數(shù)據(jù)

%讀取公汽線路的原始數(shù)據(jù)
%Pant_no中保存了
%線路編號；
%線路的票價(jià)方式（1表示單一票價(jià)，2表示分段計(jì)價(jià)）；
%線路的方式（3表示上行，4表示下行，5表示環(huán)形，6表示上行和下行一樣的）
%Path_num中保存了每條線路兩個(gè)線路的站點(diǎn)個(gè)數(shù)
%Path_states中保存了每條線路的站點(diǎn)號和順序
data_gj?=?xlsread（‘E:\代碼\data_gongjiao.xls‘‘Sheet2‘‘A1:CI2080‘）;
%篩選數(shù)據(jù)
[xy]?=?size（data_gj）;
Path_no?=?zeros（x/43）;
%求線路信息
%上行3，下行4，環(huán)形5，上下一樣的6，單一票價(jià)1，分段計(jì)價(jià)2
for?i?=?1:x/4
????Path_no（i1）?=?data_gj（（i-1）*4+11）;%保存線路編號
????Path_no（i2）?=?data_gj（（i-1）*4+21）;%保存計(jì)費(fèi)方式
????if?data_gj（（i-1）*4+31）?>?5
????????Path_no（i3）?=?6;%上行和下行一樣的情況，用6表示
????else
????????Path_no（i3）?=?data_gj（（i-1）*4+31）;%保存行駛方式
????end
end

%求每條線路的站點(diǎn)順序
Path_states?=?zeros（2*x/4y）;%保存對應(yīng)線路所經(jīng)過的站點(diǎn)
for?i?=?1:x/4
????if?data_gj（（i-1）*4+31）?>?5%如果沒有標(biāo)志，表示是上行和下行相同的
????????Path_states（（i-1）*2+1:）?=?data_gj（（i-1）*4+3:）;
????????Path_states（（i-1）*2+2:）?=?data_gj（（i-1）*4+3:）;%順序倒置
????????count?=?0;
????????for?k?=?1:y
????????????if?Path_states（（i-1）*2+2k）?<=?10000
????????????????count?=?count?+?1;
????????????end
????????end
????????if?mod（count2）?==?0
????????????for?j?=?1:count/2
????????????????temp?=?Path_states（（i-1）*2+2j）;
????????????????Path_states（（i-1）*2+2j）?=?Path_states（（i-1）*2+2count?-?j）;
????????????????Path_states（（i-1）*2+2count?-?j）?=?temp;
????????????end
????????else
????????????for?j?=?1:（count-1）/2???????????????????????????????%*************************（count/2）-1
????????????????temp?=?Path_states（（i-1）*2+2j）;
????????????????Path_states（（i-1）*2+2j）?=?Path_states（（i-1）*2+2count-j+1）;
????????????????Path_states（（i-1）*2+2count-j+1）?=?temp;
????????????end
????????end
????end
????if?data_gj（（i-1）*4+31）?==?3%等于3表示上行的
????????Path_states（（i-1）*2+11:end-1）?=?data_gj（（i-1）*4+32:end）;
????????Path_states（（i-1）*2+21:end-1）?=?data_gj（（i-1）*4+42:end）;?
????????Path_states（（i-1）*2+1end）?=?NaN;
????????Path_states（（i-1）*2+2end）?=?NaN;
????end
????if?data_gj（（i-1）*4+31）?==?5%表示環(huán)形的
????????Path_states（（i-1）*2+11:end-1）?=?data_gj（（i-1）*4+32:end）;
????????Path_states（（i-1）*2+21:end-1）?=?data_gj（（i-1）*4+42:end）;
????????Path_states（（i-1）*2+1end）?=?NaN;
????????Path_states（（i-1）*2+2end）?=?NaN;?
????end
end

%求每條線路上的站點(diǎn)數(shù)
Path_num?=?zeros（2*x/41）;%保存每條線路的站點(diǎn)數(shù)
for?i?=?1:x/4
????count1?=?0;
????count2?=?0;
????for?k?=?1:y
????????if?Path_states（（i-1）*2+1k）?<=?10000
????????????count1?=?count1?+?1;
????????end
????????if?Path_states（（i-1）*2+2k）?<=?10000
????????????count2?=?count2?+?1;
????????end
????end
????Path_num（（i-1）*2+1）?=?count1;
????Path_num（（i-1）*2+2）?=?count2;
end

%讀取地鐵線路的原始數(shù)據(jù)
%T_num保存每條地鐵線路的站點(diǎn)數(shù)和地鐵編號
%T_states保存每條地鐵線路的站點(diǎn)
%D1保存T1地鐵站和公汽站的關(guān)系
%D2保存T2地鐵站和公汽站的關(guān)系
%D1_num保存T1每個(gè)地鐵站對應(yīng)的公汽站數(shù)
%D2_num保存T2每個(gè)地鐵站對應(yīng)的公汽站數(shù)
D1?=?xlsread（‘E:\代碼\data_gongjiao.xls‘‘Sheet3‘‘A1:F23‘）;
D2?=?xlsread（‘E:\代碼\data_gongjiao.xls‘‘Sheet3‘‘A25:F42‘）;
%對地鐵數(shù)據(jù)進(jìn)行處理
T_states（1:）?=?D1（:1）‘;%第一列為地鐵1號線路
T1?=?T_states（1:）;
if?mod（length（T1）2）?==?0
????for?i?=?1:length（T1）/2
????????temp?=?T1（i）;
????????T1（i）?=?T1（l

?屬性????????????大小?????日期????時(shí)間???名稱
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?????文件???????4610??2011-08-22?05:23??25組程序包\data_gongjiao.m

?????文件?????257024??2011-08-21?10:18??25組程序包\data_gongjiao.xls

?????文件????9154161??2011-08-21?23:15??25組程序包\data_question_1.mat

?????文件????9580921??2011-08-21?22:17??25組程序包\data_question_2.mat

?????文件????????731??2011-08-22?00:27??25組程序包\decide.m

?????文件???????3488??2011-08-21?08:26??25組程序包\Dijkstra.m

?????文件????????741??2011-08-21?08:26??25組程序包\Floyd.m

?????文件????????296??2011-08-21?23:40??25組程序包\getOrder.m

?????文件????????408??2011-08-21?20:32??25組程序包\getResult.m

?????文件???????2458??2011-08-21?08:26??25組程序包\Min_data.m

?????文件???????2852??2011-08-21?22:05??25組程序包\model1_quanzhong.m

?????文件??????10078??2011-08-22?05:36??25組程序包\model2_quanzhong.m

?????文件????????921??2011-08-21?23:26??25組程序包\model_solve.m

?????文件??????38912??2011-08-22?05:23??25組程序包\Readme.doc

?????文件???????2713??2011-08-21?08:26??25組程序包\ShortestPath_Djk.m

?????文件????????658??2011-08-22?00:25??25組程序包\xuhao.m

?????目錄??????????0??2011-08-22?05:23??25組程序包

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?????????????19060972????????????????????17