資源簡(jiǎn)介
提供了移動(dòng)通信系統(tǒng)中使用不同信道估計(jì)算法的性能對(duì)比,主要是MMSE,LS和DFT
代碼片段和文件信息
clear?all;
close?all;
clc
Nfft=2048;
Ng=Nfft/4;
Nofdm=Nfft+Ng;
Nsym=1;
Nps=2;
Np=Nfft/Nps;
Nd=Nfft-Np;
Nbps=4;
M=2^Nbps;
mod_object?=?modem.qammod(‘M‘M?‘SymbolOrder‘‘gray‘);
demod_object?=?modem.qamdemod(‘M‘M?‘SymbolOrder‘‘gray‘);
Es=1;
A=sqrt(3/2/(M-1)*Es);
fs?=?9.6e6;
ts?=?1/fs;
sq2=sqrt(2);
snr_db?=?0:2:20;
for?mm?=?1:length(snr_db)
????
????SNR?=?snr_db(mm);
????rand(‘seed‘1);?randn(‘seed‘1);
????MSE?=?zeros(16);?nose?=?0;
????for?nsym=1:Nsym
????????
????????Xp?=?2*(randn(1Np)>0)-1;????%?BPSK導(dǎo)頻序列產(chǎn)生
????????msgint=randi(1Nfft-NpM);???%?用戶數(shù)據(jù)生成
????????Data?=?modulate(mod_objectmsgint)*A;
????????ip?=?0;
????????pilot_loc?=?[];
????????for?k=1:Nfft
????????????if?mod(kNps)==1
????????????????X(k)?=?Xp(floor(k/Nps)+1);
????????????????p
?屬性????????????大小?????日期????時(shí)間???名稱
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?????文件???????2952??2017-06-21?10:18??不同信道估計(jì)\Diff_Est.m
?????文件??????24126??2017-06-21?10:19??不同信道估計(jì)\diiff_est1.fig
?????文件????????595??2017-06-14?08:57??不同信道估計(jì)\interpolate1.m
?????文件????????636??2017-06-16?12:51??不同信道估計(jì)\LS_CE.m
?????文件???????1090??2017-06-16?12:51??不同信道估計(jì)\MMSE_CE.m
?????文件??????24118??2017-06-12?23:51??不同信道估計(jì)\不同信道估計(jì).fig
?????目錄??????????0??2018-02-25?10:48??不同信道估計(jì)
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????????????????53517????????????????????7
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