資源簡介
地形分塊下的匹配導航算法仿真程序,算法包括最優分塊算法和匹配定位算法的仿真

代碼片段和文件信息
%%%%%%%%%%%%%%%%%%%%%%%%%%數字地圖加載%%%%%%%%%%%%%%%%%%%%%%%%%
DEM=importdata(‘grid500_1.dat‘)
load?fz1.mat
load?fz2.mat
tao=1
R=normrnd(0tao500500);
HDEM=R+DEM;
XDEM=HDEM(101:400101:400);
CDEM(1:1001:100)=DEM(201:300201:300);
%%%%%%%%%%%%%%%%%%%%%%%%%%%加入權值%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
for?r=1:200
for?t=1:200
????XS(rt)=0;
????u=0;
???for?i=1:10
???for?j=1:10
???????for?l=((i-1)*10+1):i*10
???????for?k=((j-1)*10+1):j*10
???????????m(ij)=fz1(ij)*(1/(2*tao)^2)*(XDEM(lk)-HDEM(l+rk+t))^2;
???????????u=u+m(ij);
???????end
???????end
???end
???end
???XS(rt)=0.9*exp(-u/2000);
end
end
???contour(XS);
?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????文件????1885473??2015-03-27?10:58??基于地形分塊匹配算法定位仿真(原始程序)\DEM.mat
?????文件????1885663??2015-03-27?12:32??基于地形分塊匹配算法定位仿真(原始程序)\fz1.mat
?????文件????1885663??2015-03-27?12:33??基于地形分塊匹配算法定位仿真(原始程序)\fz2.mat
?????文件????4001000??2011-03-25?15:52??基于地形分塊匹配算法定位仿真(原始程序)\grid500_1.dat
?????文件????1860816??2015-03-27?15:20??基于地形分塊匹配算法定位仿真(原始程序)\MAP.mat
?????文件????????647??2015-04-02?13:49??基于地形分塊匹配算法定位仿真(原始程序)\POSITION.asv
?????文件????????647??2015-04-02?13:52??基于地形分塊匹配算法定位仿真(原始程序)\POSITION.m
?????文件????????536??2015-03-27?18:43??基于地形分塊匹配算法定位仿真(原始程序)\POSITION1.asv
?????文件????????553??2015-04-02?13:48??基于地形分塊匹配算法定位仿真(原始程序)\POSITION1.m
?????文件?????276787??2015-04-02?14:00??基于地形分塊匹配算法定位仿真(原始程序)\似然函數等值線圖.fig
?????文件?????340049??2015-04-02?14:04??基于地形分塊匹配算法定位仿真(原始程序)\似然函數等值線圖(分塊).fig
?????文件?????644918??2015-04-02?13:34??基于地形分塊匹配算法定位仿真(原始程序)\分塊的匹配結果.fig
?????文件?????507413??2015-04-02?13:35??基于地形分塊匹配算法定位仿真(原始程序)\未分塊的匹配結果.fig
?????目錄??????????0??2015-04-02?13:55??基于地形分塊匹配算法定位仿真(原始程序)
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?????????????13290165????????????????????14
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