資源簡介
matlab 信道估計仿真,比較了最小均方差和二乘法的性能
代碼片段和文件信息
%------------------------------------------
%?EE359?final?project?Fall?2002
%?Channel?estimation?for?a?MIMO-OFDM?system
%?By?Shahriyar?Matloub???????????????
%------------------------------------------
clear?all;
%close?all;
i=sqrt(-1);
Rayleigh=1;
AWGN=0;?????????????????????????????%?for?AWGN?channel?
MMSE=0;?????????????????????????????%?estimation?technique
Nsc=64;?????????????????????????????%?Number?of?subcarriers
Ng=16;??????????????????????????????%?Cyclic?prefix?length
SNR_dB=[0?5?10?15?20?25?30?35?40];??%?Signal?to?noise?ratio
Mt=2;???????????????????????????????%?Number?of?Tx?antennas
Mr=2;???????????????????????????????%?Number?of?Rx?antennas
pilots=[1:Nsc/Ng:Nsc];??????????????%?pilot?subcarriers?
DS=5;??????????????????????????????%?Delay?spread?of?channel
iteration_max=200;
%%%%%%%%%%%%%%%%%%%%%%%%%%%%
%?Channel?impulse?response?%
%%%%%%%%%%%%%%%%%%%%%%%%%%%%
if?(Rayleigh)
????N=50;
????
????fm=100;
????B=20e3;
????fd=(rand(1N)-0.5)*2*fm;
????theta=randn(1N)*2*pi;
- 上一篇:交友系統源代碼
- 下一篇:WinRing0_1_3_0
評論
共有 條評論