資源簡介
用RBF神經網絡構造內部模型,并求得逆模型,整個閉環過程能良好的控制跟蹤
代碼片段和文件信息
%load?trule
%clc;clear?all;
load?inv_NET
global?percent1?percent2
global?r
percent1=0.15;
percent2=-0.05;
n=24;ff=13;landa=30001.1;alfa=2.317;????%操作條件
UA=9803*3.6;
Ps=0.1013;
F=100;
%Zf=0.5;
flag=1;
beta=0.75;
options=odeset(‘RelTol‘1e-6‘AbsTol‘1e-9);
X0=[0.89135 0.87175 0.84764 0.81825 0.78294 0.74141 0.69391 0.64145 0.58582 0.52937 0.47458 0.42354 0.37765 0.3323 0.28676 0.2429 0.20245 0.16661 0.13599 0.11057 0.08992 0.073403 0.060311 0.049978?0.5?0.3195];
[tX2]=ode15s(‘m_dync2a‘0:0.01:8.02X0options);%step?change
Xt=X2(:1);%save?the?change?data?of?the?top?level?of?ITCDIC
Xb=X2(:n);%save?the?change?data?of?the?bottom?level?of?ITCDIC
????????
%figure(1)
%plot(tXt);
%figure(2)
%plot(tXb‘r‘);
?for?k=150:1:length(X2)
?X2(kn+2)=0.3195*(1+percent2);
?end
?Pr=X2(:n+2);
for?k=150:1:length(X2)
X2(kn+1)=0.5*(1+percent1);
end
q=X2(:n+1);
figure(11)
plot(tPr‘g‘tq‘k‘);
Y0(1)=alfa*X0(1)/((alfa-1)*X0(1)+1);
output(:1)=[
?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????文件???????3665??2011-06-12?00:38??NNimc程序\invNN_esti.m
?????文件???????3272??2011-06-12?00:48??NNimc程序\inv_NET.mat
?????文件????????134??2011-06-01?19:00??NNimc程序\main_nnimc.m
?????文件????????969??2011-06-01?17:19??NNimc程序\m_dync2a.m
?????文件??????13198??2011-06-15?13:58??NNimc程序\NET.mat
?????文件???????3118??2011-06-12?01:19??NNimc程序\nnctrler.asv
?????文件???????3118??2011-06-12?01:21??NNimc程序\nnctrler.m
?????文件???????3177??2011-06-12?01:04??NNimc程序\NNesti.m
?????文件???????3552??2011-06-02?00:27??NNimc程序\nnimcsimu.m
?????文件???????1225??2011-06-12?00:33??NNimc程序\NNsim.m
?????文件???????1017??2011-06-12?00:47??NNimc程序\NNsiminv.m
?????文件???????1571??2011-06-12?01:02??NNimc程序\nnsysid.m
?????文件???????1344??2011-05-31?16:31??NNimc程序\tcd_dcy2.m
?????文件???????1061??2011-06-01?17:26??NNimc程序\tmodel.m
?????目錄??????????0??2012-01-05?22:13??NNimc程序
-----------?---------??----------?-----??----
????????????????40421????????????????????15
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