function?result=Ackley（x）
%Ackley?函數(shù)
%輸入x給出相應(yīng)的y值在x=（00…0）?處有全局極小點(diǎn)0為得到最大值，返回值取相反數(shù)
%編制人：
%編制日期：
[rowcol]=size（x）;
if?row>1
????error（‘輸入的參數(shù)錯(cuò)誤‘）;
end
result=-20*exp（-0.2*sqrt（（1/col）*（sum（x.^2））））-exp（（1/col）*sum（cos（2*pi.*x）））+exp（1）+20;
result=-result;

?屬性????????????大小?????日期????時(shí)間???名稱
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?????文件????????317??2013-07-02?02:15??niuPSO\Ackley.m

?????文件???????4663??2013-07-02?02:15??niuPSO\baseStepPso.m

?????文件????????220??2013-07-02?02:15??niuPSO\DrawAckley.m

?????文件????????236??2013-07-02?02:15??niuPSO\DrawGriewank.m

?????文件????????383??2013-07-02?02:15??niuPSO\DrawObjGraphic.asv

?????文件????????534??2013-07-02?02:15??niuPSO\DrawObjGraphic.m

?????文件????????230??2013-07-02?02:15??niuPSO\DrawRastrigin.m

?????文件????????259??2013-07-02?02:15??niuPSO\DrawRosenbrock.m

?????文件????????188??2013-07-02?02:15??niuPSO\DrawSchaffer.m

?????文件?????????45??2013-07-02?02:15??niuPSO\erwei.asv

?????文件?????????46??2013-07-02?02:15??niuPSO\erwei.m

?????文件????????278??2013-07-02?02:15??niuPSO\Griewank.m

?????文件????????920??2013-07-02?02:15??niuPSO\hunheTest.m

?????文件???????7936??2013-07-02?02:15??niuPSO\HybridStepPso.m

?????文件???????2200??2013-07-02?02:15??niuPSO\InitSwarm.m

?????文件???????4290??2013-07-02?02:15??niuPSO\LocalInitSwarm.m

?????文件???????5672??2013-07-02?02:15??niuPSO\LocalPsoProcessByCircle.m

?????文件???????6943??2013-07-02?02:15??niuPSO\LocalStepPsoByCircle.m

?????文件???????5651??2013-07-02?02:15??niuPSO\PsoProcess.m

?????文件????????223??2013-07-02?02:15??niuPSO\Rastrigin.m

?????文件????????379??2013-07-02?02:15??niuPSO\Rosenbrock.m

?????文件????????281??2013-07-02?02:15??niuPSO\Schaffer.m

?????文件???????1503??2013-07-02?02:15??niuPSO\testlinyu.m

?????目錄??????????0??2016-02-25?09:23??niuPSO

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????????????????43397????????????????????24