資源簡介
zw_BFS.zip

代碼片段和文件信息
%%輸入數據
%?zhilu=[
%?????1?2???;
%?????1?6???;
%?????1?7???;
%?????2?3???;
%?????2?8???;
%?????3?4???;
%?????3?9???;
%?????4?5???;
%?????4?10??;
%?????5?6???;
%?????5?11??;
%?????6?12??;
%?????7?8???;
%?????7?12??;
%?????8?9???;
%?????9?10??;
%?????10?11?;
%?????11?12?;?
%????];
zhilu1=[?
????0?3?;
????1?2?;
????2?3?;
????2?4?;
????3?5?;
????5?7?;
????5?9?;
????7?6?;
????9?8?
????];
%%將輸入支路矩陣轉化為鄰接矩陣
[m1n1]=size(zhilu1);
zhilu=zhilu1+ones(m1n1);
n=max(max(zhilu(:1:2)));?????????????????%獲取支路節點數
G=zeros(n);???????
for?i=1:m1
??m2=zhilu(i1);
??n2=zhilu(i2);
??G(m2n2)=1;
??G(n2m2)=1;
end
%%尋找與第一個頂點相關聯的頂點
W=zeros(1n);????????????????????????????%儲存標號后的節點,節點順序從小到大排列
l=0;
v=1;
a1=find(G(v:)==1);??????????????????????%尋找與第一個頂點相關聯節點并標號
G(va1)=2;???????????????????????????????
G(a1v)=2;
W(a1)=l+1;
S1=union(va1);
l=l+1;
%%尋找與標號為l的頂點相關聯且未被標號的頂點集合
while?~isempty(G==1)
????a1=find(G(S1:)==1);
????t=length(S1);
????d=[];
????for?i=1:length(a1)
????????if?a1(i)/t>floor(a1(i)/t)
????????????t2=floor(a1(i)/t)+1;
????????else
????????????t2=floor(a1(i)/t);
????????end??????????????????????????????%col
????????if?isempty(intersect(dt2))
????????????d=union(dt2);
????????end
????end
????d1=?setdiff(dS1);
????%對找到的頂點集合進行標號
????if?isempty(d1)
????????break;
????else?
????????W(d1)=l+1;
????????G1=G(S1:);
????????G1(a1)=2;
????????G(S1:)=G1;
????????G(:S1)=G1‘;
????????S1=union(S1d1);
????????l=l+1;
????end
????
end
?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????文件????????1669??2019-03-19?14:25??\4326770_BFS.m
?????文件??????????36??2019-03-19?14:25??\no.txt
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