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資源簡(jiǎn)介

MATLAB強(qiáng)化學(xué)習(xí)代碼包,用于解決多步?jīng)Q策模型(網(wǎng)格迷宮問(wèn)題)的Sarsa算法。
編程與算法的詳細(xì)說(shuō)明可參看我的專(zhuān)欄:https://blog.csdn.net/weixin_43723517/category_9676083.html
"I thought what I'd do was I'd pretend I was one of those deaf-mutes, or should I?"

資源截圖

代碼片段和文件信息

function?outputxy=movement(numinputxyWindyworld)

wind=[Windyworld.windy(inputxy(1)inputxy(2))Windyworld.windx(inputxy(1)inputxy(2))];??%注意:第一個(gè)坐標(biāo)為y坐標(biāo),第二個(gè)坐標(biāo)為x坐標(biāo)
outputxy=inputxy+wind;

if?num==1??%(z=1:+x)(z=2:-x)(z=3:+y)(z=4:-y)
????outputxy=outputxy+[01];??%z=1?右移一格
else?if?num==2
????????outputxy=outputxy+[0-1];
????else?if?num==3
????????????outputxy=outputxy+[10];
????????else?if?num==4
????????????????outputxy=outputxy+[-10];
????????????end
????????end
????end
end

?屬性????????????大小?????日期????時(shí)間???名稱(chēng)
-----------?---------??----------?-----??----

?????文件????????535??2019-12-29?20:26??Sarsa\movement.m

?????文件????????412??2020-01-16?08:15??Sarsa\tcegreedy.m

?????文件???????2485??2020-01-19?19:36??Sarsa\WGW_Sarsa.m

?????目錄??????????0??2020-01-19?19:35??Sarsa

-----------?---------??----------?-----??----

?????????????????3432????????????????????4


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