資源簡介
并聯機器人,Delta機器人正逆解,MATLAB程序,驗證可行

代碼片段和文件信息
function?[position]?=?forward_delta(thetasgeometry)
R=geometry(1);?
r=geometry(2);
l1=geometry(3);
l2=geometry(4);
theta1=thetas(1)*pi/180;
theta2=thetas(2)*pi/180;
theta3=thetas(3)*pi/180;
beta1=(1-1)*2*pi/3-pi/6;
beta2=(2-1)*2*pi/3-pi/6;
beta3=(3-1)*2*pi/3-pi/6;
OB1=R*[cos(beta1);sin(beta1);0];
OB2=R*[cos(beta2);sin(beta2);0];
OB3=R*[cos(beta3);sin(beta3);0];
B1C1=l1*[cos(beta1)*cos(theta1);sin(beta1)*cos(theta1);-sin(theta1)];
B2C2=l1*[cos(beta2)*cos(theta2);sin(beta2)*cos(theta2);-sin(theta2)];
B3C3=l1*[cos(beta3)*cos(theta3);sin(beta3)*cos(theta3);-sin(theta3)];
OC1=OB1+B1C1;
OC2=OB2+B2C2;
OC3=OB3+B3C3;
O1A1=r*[cos(beta1);sin(beta1);0];
O1A2=r*[cos(beta2);sin(beta2);0];
O1A3=r*[cos(beta3);sin(beta3);0];
OB=OC1-O1A1;
OC=OC2-O1A2;
OD=OC3-O1A3;
BC=OB-OC;
CD=OC-OD;
DB=OD-OB;
a=norm(BC);
b=norm(CD);
c=norm(DB);
p=(a+b+c)/2;
s=sqrt(p*(p-a)*(p-b)*(p-c));
N_BF=a*b*c/(4*s);
N_BE=a/2;
N_EF=sqrt(N_BF^2-N_BE^2);
n_EF=cross(cross(BCCD)BC)/a*b*a;
EF=N_EF*n_EF;
OE=(OB+OC)/2;
OF=OE+EF;
N_FO1=sqrt(l2^2-N_BF^2);
n_FO1=cross(BCCD)/a*b;
FO1=N_FO1*n_FO1;
OO1=OF+FO1;
position=OO1;
?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????文件???????1155??2013-08-01?15:53??forward_delta.m
?????文件????????997??2013-08-01?15:53??inverse_delta.m
-----------?---------??----------?-----??----
?????????????????2152????????????????????2
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