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低秩表示MATLAB代碼,自己親自測試過,是有效可用的呢

代碼片段和文件信息
function?[]?=?demo()
A?=?randn(100200);
X?=?randn(100100);
lambda?=?0.01;
disp(‘solve?min?|Z|_*?+?lambda?|E|_21?s.t.?X?=?AZ?+?E?by?exact?ALM?...‘);
tic;
[Z1E1]?=?solve_lrr(XAlambda00);
obj1?=?sum(svd(Z1))?+?lambda*sum(sqrt(sum(E1.^21)));
toc;
disp([‘objective?value=‘?num2str(obj1)]);
disp(‘solve?min?|Z|_*?+?lambda?|E|_21?s.t.?X?=?AZ?+?E?by?inexact?ALM?...‘);
tic;
[Z2E2]?=?solve_lrr(XAlambda01);
obj2?=?sum(svd(Z2))?+?lambda*sum(sqrt(sum(E2.^21)));
toc;
disp([‘objective?value=‘?num2str(obj2)]);
diff?=?max(max(abs(Z1?-?Z2)));
warning([‘difference?of?the?solution?found?by?those?two?approaches:?|Z1?-?Z2|_inf=‘?num2str(diff)]);
disp(‘solve?min?|Z|_*?+?lambda?|E|_1?s.t.?X?=?AZ?+?E?by?exact?ALM?...‘);
tic;
[Z1E1]?=?solve_lrr(XAlambda10);
obj1?=?sum(svd(Z1))?+?lambda*sum(sqrt(sum(E1.^21)));
toc;
disp([‘objective?value=‘?num2str(obj1)]);
disp(‘solve?min?|Z|_*?+?lambda?|E|_1?s.t.?X?=?AZ?+?E?by?inexact?ALM?...‘);
tic;
[Z2E2]?=?solve_lrr(XAlambda11);
obj2?=?sum(svd(Z2))?+?lambda*sum(sqrt(sum(E2.^21)));
toc;
disp([‘objective?value=‘?num2str(obj2)]);
diff?=?max(max(abs(Z1?-?Z2)));
warning([‘difference?of?the?solution?found?by?those?two?approaches:?|Z1?-?Z2|_inf=‘?num2str(diff)?]);
?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????文件????????1223??2013-09-09?14:06??lrr\demo.m
?????文件????????3005??2013-10-06?18:10??lrr\exact_alm_lrr_l1v2.m
?????文件????????2899??2013-10-06?18:10??lrr\exact_alm_lrr_l21v2.m
?????文件????????1749??2013-10-06?18:09??lrr\inexact_alm_lrr_l1.m
?????文件????????1722??2013-10-06?18:13??lrr\inexact_alm_lrr_l21.m
?????文件?????????289??2013-09-25?16:22??lrr\solve_l1l2.m
?????文件????????1306??2013-10-06?18:14??lrr\solve_lrr.m
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