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  • 大小: 3KB
    文件類型: .m
    金幣: 1
    下載: 1 次
    發布日期: 2021-05-14
  • 語言: Matlab
  • 標簽: pts??ofdm??

資源簡介

采用了隨機分割和交織分割的聯合分割方式和多次迭代的方法來選出相位因子。

資源截圖

代碼片段和文件信息

clear?all;?clc;?close?all;

K?=?128;????????????????????????????????????????????????????????????????????%?SIZE?OF?FFT?
V?=?4;???????????????????????????????????????????????????????????????????????%?NUMBER?OF?SELECTIONS
QPSK_Set??=?[1?-1?j?-j];
?

MAX_SYMBOLS??=?1e5;
PAPR_Orignal?=?zeros(1MAX_SYMBOLS);

%??original
for?nSymbol=1:MAX_SYMBOLS
????Index?=?randint(1Klength(QPSK_Set))+1;%1*128
????X=?QPSK_Set(Index(1:));???????????????????????????????????????????????%?Orignal?Frequency?domain?signal
????x?=?ifft(X[]2);?????????%1*128??????????????????????????????????????????????%?Time?domain?signal
????Signal_Power0?=?abs(x.^2);
????Peak_Power0???=?max(Signal_Power0[]2);
????Mean_Power0???=?mean(Signal_Power02);
????PAPR_Orignal(nSymbol)?=?10*log10(Peak_Power0./Mean_Power0);
end

%隨機交織+遍歷搜索

PAPR_PTS1?=?zeros(1MAX_SYMBOLS);

for?nSymbol=1:MAX_SYMBOLS
????Index1?=?randint(1Klength(QPSK_Set))+1;
????X1?=?QPSK_Set(Index1(1:));???????????????????????????????????????????????%?Orignal?Frequency?domain?signal
????l1=length(X1);
????z1=zeros(Vl1);
????pilot1=randperm(l1/2);
????for?k1=1:V/2?
????????z1(k1pilot1(k1:V/2:l1/2))=X1(pilot1(k1:V/2:l1/2));%隨機
????end
????for?k1=(V/2)+1:V
????????z1(k1k1-2+l1/2:V/2:l1)=X1(k1-2+l1/2:V/2:l1);%交織
????end
????a1=?ifft(z1[]2);

??
???b(1)=1;?
???b(2)=1;
???b(3)=1;
???b(4)=1;
?
???b=[b(1)?b(2)?b(3)?b(4)];
???aa1=sum(a1.*repmat(b.‘1K));
?????
??
????Signal_P

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