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    文件類型: .zip
    金幣: 2
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    發(fā)布日期: 2021-05-15
  • 語言: Matlab
  • 標(biāo)簽: matlab??AHE??

資源簡(jiǎn)介

在matlab中實(shí)現(xiàn)了自適應(yīng)直方圖均衡(AHE),親測(cè)有效。

資源截圖

代碼片段和文件信息

%this?is?the?main?function
clear
clc;
img=((imread(‘24.jpg‘)));
figure;
imshow(img);
result=ahe(img8150);
figure;
imshow(result);

disp?‘done‘;
%%
function?img_new=ahe(imggridlimit)?
????
????img_new=img;?%img_new?is?the?img?after?AHE
????[mn]=size(img);??
????
????%ECR
????
????grid_cols=grid;
????grid_rows=grid;

????grid_width=int32(fix(m/grid_cols));
????grid_height=int32(fix(n/grid_rows));
????
????map=zeros(grid_colsgrid_rows256);
????
????%for?each?gridwe?create?their?mapping?function
????for?i=1:grid_cols
????????for?j=1:grid_rows
????????????map(ij:)=MakeHistogram(img1+(i-1)*grid_width1+(j-1)*grid_heightgrid_widthgrid_heightlimit);?
????????end
????end
????%interpolate
????%boundary?cases?I?followed?the?Karel?Zuiderveld‘s?implement(C?version)
????xi?=?1;?
????for?i?=?1:grid_cols+1?
????????if?i?==?1?
????????????subx?=?grid_width/2;?
????????????xu?=?1;?
????????????xd?=?1;?
????????elseif?i?==?grid_cols+1?
????????????subx?=?grid_width/2;?
????????????xu?=??grid_cols;?
????????????xd?=??grid_cols;?
????????else?
????????????subx?=?grid_width;?
????????????xu?=?i?-?1;?
????????????xd?=?i;?
????????end?
????????yi?=?1;?
????????for?j?=?1:grid_rows+1
????????????if?j?==?1?
????????????????suby?=?grid_height/2;?
????????????????yl?=?1;?
????????????????yr?=?1;?
????????????elseif?j?==?grid_rows+1
????????????????suby?=?grid_height/2;?
????????????????yl?=?grid_rows;?
????????????????yr?=?grid_rows;?
????????????else?
????????????????suby?=?grid_height;?
????????????????yl?=?j?-?1;?
????????????????yr?=?j;?
????????????end?
????????????UL?=?map(xuyl:);?
????????????UR?=?map(xuyr:);?
????????????DL?=?map(xdyl:);?
????????????DR?=?map(xdyr:);?

????????????subimg?=?img(xi:xi+subx-1yi:yi+suby-1);?
????????????subimg?=?Interpolate(subimgULURDLDRsubxsuby);?
????????????img_new(xi:xi+subx-1yi:yi+suby-1)?=?subimg;?
????????????yi?=?yi?+?suby;?
????????end?
????????xi?=?xi?+?subx;?
????end?
end

%%
function?map=MakeHistogram(imgstartxstartywidthheightlimit)?
%make?histogram
hist=zeros(1256);?
????????for?i=startx:startx+width-1?
????????????for?j=starty:starty+height-1
????????????????value=img(ij);
????????????????hist(value+1)=hist(value+1)+1;
????????????end?
????????end?
%clip?and?allienate?noise

????????if?(limit>0)
????????excess?=?0;?
????????%get?the?excess
????????for?degree?=?1:256?
????????????excess=excess+max(0hist(degree)-limit);?
????????end?
????????ts=limit-excess/256;
????????avginc=excess/256;
????????%cut?them?and?compensate?other?gray?level
????????for?degree=1:256
????????????if?(hist(degree)>limit)
????????????????hist(degree)=limit;
????????????end
????????????%when?compensatingshould?not?larger?than?limit
????????????if?(hist(degree)>ts)
????????????????excess=excess-(limit-hist(degree));
????????????????hist(degree)=limit;
????????????else
????????????????hist(degree)=hist(deg

?屬性????????????大小?????日期????時(shí)間???名稱
-----------?---------??----------?-----??----
?????文件????????4292??2019-04-07?21:37??two.m

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