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    文件類型: .rar
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    發(fā)布日期: 2021-05-23
  • 語(yǔ)言: Matlab
  • 標(biāo)簽: 倒立擺??matlab??演示??

資源簡(jiǎn)介

這是一個(gè)演示直線二級(jí)倒立擺的matlab運(yùn)行模型,這個(gè)模型能夠根據(jù)仿真數(shù)據(jù)動(dòng)畫演示出二級(jí)倒立擺的運(yùn)動(dòng)情況。

資源截圖

代碼片段和文件信息

function?Invertedpendulum(carp1p2)
%car=0;p1=pi;p2=pi;
l1=1;l2=1;
%%?初始化坐標(biāo)系?繪制小車
car_x=-0.5+car:1:0.5+car;
car_y=0.3*ones(1length(car_x));
car_d=0*ones(1length(car_x));
plot(car_xcar_y‘k‘);
hold?on
plot(car_xcar_d‘k‘);
hold?on
car_h=linspace(00.310);
car_l=-0.5+car*ones(110);
car_r=0.5+car*ones(110);
plot(car_lcar_h‘k‘);
hold?on
plot(car_rcar_h‘k‘);
set(?gca?‘XLim‘?[-4?4]?);
set(?gca?‘YLim‘?[-4?4]?)
set(?gca?‘XTick‘?-4:0.5:4);?
set(?gca?‘YTick‘?-4:0.5:4?);
hold?on
%%?繪制倒立擺桿1
p1_x0=car;p1_y0=0.3;
if?mod(p1pi)==0
????p1_x=p1_x0*ones(110);
????if?mod(p1/pi2)==0
????????p1_y=linspace(p1_y0p1_y0+l110);
????else
????????p1_y=linspace(p1_y0p1_y0-l110);
????end
else
????p1_k=cot(p1);
????p1_b=p1_y0-p1_k*p1_x0;
????p1_x=linspace(min(p1_x0p1_x0+sin(p1)*l1)max(p1_x0p1_x0+sin(p1)*l1)100);
????p1_y=p1_k*p1_x+p1_b;
end
plot(p1_xp1_y‘r‘‘LineWidth‘2);
hold?on
%%?繪制倒立擺桿2
p2_x0=p1_x0+sin(p1)*l1;p2_y0=cos(p1)*l1+0.3;
if?mod(p2pi)==0
????p2_x=p2_x0*ones(110);
????if?mod(p2/pi2)==0
????????p2_y=linspace(p2_y0p2_y0+l210);
????else
????????p2_y=linspace(p2_y0p2_y0-l210);
????end
else
????p2_k=cot(p2);
????p2_b=p2_y0-p2_k*p2_x0;
????p2_x=linspace(min(p2_x0p2_x0+sin(p2)*l2)max(p2_x0p2_x0+sin(p2)*l2)100);
????p2_y=p2_k*p2_x+p2_b;
end
plot(p2_xp2_y‘b‘‘LineWidth‘2);
hold?off


?屬性????????????大小?????日期????時(shí)間???名稱
-----------?---------??----------?-----??----

?????文件????????224??2012-10-23?12:28??nemoIP.m

?????文件???????1898??2012-10-23?12:11??nemo.mat

?????文件???????1402??2012-10-23?12:33??Invertedpendulum.m

-----------?---------??----------?-----??----

?????????????????3524????????????????????3


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