91av视频/亚洲h视频/操亚洲美女/外国一级黄色毛片 - 国产三级三级三级三级

  • 大小: 5KB
    文件類型: .rar
    金幣: 2
    下載: 0 次
    發布日期: 2021-05-27
  • 語言: Matlab
  • 標簽: matlab??PSO??

資源簡介

代碼利用粒子群算法對帶時間窗的車輛路徑規劃問題進行了求解,代碼進行了詳細的注釋,易于理解和進行修改,內置了一組數據,為可執行的代碼。

資源截圖

代碼片段和文件信息

%%----評估粒子---%%
%是否為可行解--判斷依據:各車輛是否超重超重
%根據目標函數計算目標值,找出粒子群的gbest和各粒子的pbest
%ijkctj1j2
function?[gbestXv?gbestXr?fav]=eval(XvXryPEPLCTSTgvnnmspeedDSw)
fav=zeros(n1);???%%%
bm=linspace(1nn);?
ET=CT(:1);
LT=CT(:2);
g;
t1=0;
for?i=1:n
????Xvi=Xv(i:);??%獲取任務對應車輛編號的粒子行
????Xri=Xr(i:);???%獲取車輛對應任務順序行
????st=zeros(vn+1m);
????st(1:)=linspace(1mm);
????t=0;
????bmzys=zeros(1);
????sg=zeros(1vn);?%存儲沒輛車的貨物
????ST1=zeros(1vn);%存儲每輛車的時間懲罰
????juli=zeros(1vn);
????%對每個粒子的Xv和Xr進行解碼
????for?j=1:vn
????????colv=find(Xvi==j);
????????for?k=1:length(colv)
????????????st(j+1colv(k))=Xri(colv(k));?%獲取每一輛車的Xr值
????????end
????????st0=st(1:)‘;
????????stj=st(j+1:)‘;
????????sst=[st0?stj];
????????pxst=sortrows(sst2);??%%進行排序獲取每輛車接送任務的順序
????????for?c=1:m
????????????if?pxst(c2)~=0
????????????????t=t+1;
????????????????cxh(t)=pxst(c1);??%獲取每輛車的進行各項任務的編號
????????????end
????????end
????????for?j1=1:t
????????????sg(j)=sg(j)+g(cxh(j1));???%%每輛車所載貨物
????????????if?j1~=t
????????????????juli(j)=juli(j)+DS(1cxh(1))+DS(cxh(j1)cxh(j1+1));??%每輛車途經距離
????????????else
????????????????juli(j)=juli(j)+DS(cxh(t)1);??%每輛車途經距離
????????????end
????????????if?t~=1
????????????????if?j1~=t
????????????????cxh(j1+1);
????????????????cxh(j1);
??????????????????ST0=DS(1cxh(1))/speed+ST(cxh(1))+PE*max(ET(cxh(1))-ST(1)0)+PL*max(LT(cxh(1))-ST(1)0);??%每輛車途經第一個節點時的時間(不包括時間懲罰)
??????????????????ST1(j)=ST0+ST1(j)+DS(cxh(j1)cxh(j1+1))/speed+PE*max(ET(cxh(j1+1))-ST1(j)0)+PL*max(LT(cxh(j1+1))-ST1(j)0)+ST(cxh(j1));
????????????????else
????????????????????ST1(j)=ST1(j)+DS(cxh(t)1)/speed;
????????????????end
????????????else
????????????????ST0=DS(1cxh(1))/speed+ST(cxh(1))+PE*max(ET(cxh(1))-ST(1)0)+PL*max(LT(cxh(1))-ST(1)0);
????????????????ST1(j)=ST0;
????????????end
????????end
????????if?sum(sg)>w??%%約束條件判斷
????????????t1=t1+1;
???????????bmzys(t1)=j;
????????end
????end
????%%%目標函數計算
????fav(i)=y*sum(juli)+sum(ST1);
end
bmzyscl=find(bmzys~=0);??%%讀取不滿足約束的粒子
for?j3=1:length(bmzyscl)
????bm(bmzys(bmzyscl(j3)))=0;
????fav(bmzys(bmzyscl(j3)))=inf;
end
bm1=bm(bm~=0);
for?j4=1:length(bmzyscl)
????lh=length(bm1);
????lh1=round(rand*(lh-2)+1);
????Xv(j4:)=Xv(lh1:);
end
gbestj=find(fav==min(fav));
gbestXr=Xr(gbestj:);
gbestXv=Xv(gbestj:);



????

????????
????????
????
????????
????????
????????

?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----

?????文件????????217??2018-12-21?20:56??待時間窗車輛路徑規劃模型求解matlab代碼\CT.mat

?????文件????????605??2018-12-21?21:09??待時間窗車輛路徑規劃模型求解matlab代碼\DS.mat

?????文件???????2630??2018-12-22?17:21??待時間窗車輛路徑規劃模型求解matlab代碼\eval.m

?????文件????????193??2018-12-21?20:52??待時間窗車輛路徑規劃模型求解matlab代碼\g.mat

?????文件???????4326??2018-12-22?17:20??待時間窗車輛路徑規劃模型求解matlab代碼\main.m

?????文件????????198??2018-12-21?20:54??待時間窗車輛路徑規劃模型求解matlab代碼\ST.mat

?????目錄??????????0??2019-01-01?13:43??待時間窗車輛路徑規劃模型求解matlab代碼

-----------?---------??----------?-----??----

?????????????????8169????????????????????7


評論

共有 條評論