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資源簡(jiǎn)介

1.Matlab程序,附帶超詳細(xì)批注 2.分別用牛頓拉夫遜法和PQ分解法求解潮流 3.算例采用華科大電分下冊(cè)例11-5作為驗(yàn)證,計(jì)算結(jié)果完全一致

資源截圖

代碼片段和文件信息

%?function:?計(jì)算雅可比矩陣
function?[?J?]?=?Jacobi(?nmUcitaBGPiQi?)
%雅可比矩陣的計(jì)算
%分塊?H?N?K?L
%i!=j時(shí)
for?i=1:n-1
for?j=1:n-1
H(ij)=-U(i)*U(j)*(G(ij)*sin(cita(i)-cita(j))-B(ij)*cos(cita(i)-cita(j)));
end
end
for?i=1:n-1
for?j=1:m
N(ij)=-U(i)*U(j)*(G(ij)*cos(cita(i)-cita(j))+B(ij)*sin(cita(i)-cita(j)));
end
end
for?i=1:m
for?j=1:n-1
K(ij)=U(i)*U(j)*(G(ij)*cos(cita(i)-cita(j))+B(ij)*sin(cita(i)-cita(j)));
end
end
for?i=1:m
for?j=1:m
L(ij)=-U(i)*U(j)*(G(ij)*sin(cita(i)-cita(j))-B(ij)*cos(cita(i)-cita(j)));
end
end
%i==j時(shí)由于m<=n-1
for?i=1:n-1
H(ii)=U(i)^2*B(ii)+Qi(i);
end
for?i=1:m
N(ii)=-U(i)^2*G(ii)-Pi(i);
end
for?i=1:m
K(ii)=U(i)^2*G(ii)-Pi(i);
end
for?i=1:m
L(ii)=U(i)^2*B(ii)-Qi(i);
end

%合成雅可比矩陣
J=[H?N;K?L];

end


?屬性????????????大小?????日期????時(shí)間???名稱
-----------?---------??----------?-----??----

?????文件????????832??2018-12-20?10:39??牛頓拉夫遜法&PQ分解法計(jì)算潮流\Jacobi.m

?????文件????????265??2018-12-21?10:30??牛頓拉夫遜法&PQ分解法計(jì)算潮流\Polar_Correct.m

?????文件???????4576??2018-12-21?15:42??牛頓拉夫遜法&PQ分解法計(jì)算潮流\PowerFlow.m

?????文件????????329??2018-12-21?10:30??牛頓拉夫遜法&PQ分解法計(jì)算潮流\PQ_Correct.m

?????文件????????558??2018-12-20?10:54??牛頓拉夫遜法&PQ分解法計(jì)算潮流\Unbalanced.m

?????目錄??????????0??2018-12-26?14:15??牛頓拉夫遜法&PQ分解法計(jì)算潮流

-----------?---------??----------?-----??----

?????????????????6560????????????????????6


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