資源簡(jiǎn)介
matlab代碼,直接應(yīng)用輸入輸出數(shù)據(jù)辨識(shí)傳遞函數(shù)模型,且包含多種傳遞函數(shù)模型結(jié)構(gòu)的辨識(shí)

代碼片段和文件信息
%計(jì)算辨識(shí)優(yōu)化目標(biāo)函數(shù)子程序,模型結(jié)構(gòu)G(s)=V1/(V2s+1)^V3
function?[Qy1]=psoi_obj_1(V)
global?Ts?m?u?y?n
Q=0;
%計(jì)算差分方程及目標(biāo)函數(shù)
x(1:n)=0;
DT=2;
A=exp(-DT/V(2));B=1-A;
for?k=1:m
????for?i=1:Ts/DT
????????x(1)=A*x(1)+V(1)*B*u(k);
????????for?j=2:n
????????????x(j)=A*x(j)+B*x(j-1);
????????end
???end
???y1(k)=x(n);
???Q=Q+(y(k)-y1(k))*(y(k)-y1(k));
end??
?屬性????????????大小?????日期????時(shí)間???名稱
-----------?---------??----------?-----??----
?????目錄???????????0??2016-03-24?12:20??PSO辨識(shí)五種\
?????文件????????5705??2016-01-20?16:58??PSO辨識(shí)五種\bianshishuju.mat
?????文件????????1856??2016-01-20?16:58??PSO辨識(shí)五種\data_step_io.mat
?????文件?????????375??2016-01-20?16:58??PSO辨識(shí)五種\psoi_obj_1.m
?????文件????????1037??2016-01-20?16:58??PSO辨識(shí)五種\psoi_obj_2.m
?????文件?????????556??2016-01-20?16:58??PSO辨識(shí)五種\psoi_obj_3.m
?????文件?????????455??2016-01-20?16:58??PSO辨識(shí)五種\psoi_obj_4.m
?????文件???????12094??2016-01-20?16:58??PSO辨識(shí)五種\PSO_MAIN.asv
?????文件???????12200??2016-01-20?16:58??PSO辨識(shí)五種\PSO_MAIN.m
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