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資源簡(jiǎn)介

仿真產(chǎn)生的雷達(dá)信號(hào)脈沖,并使用聚類方法進(jìn)行分選,代碼精辟詳細(xì)。值得借鑒!

資源截圖

代碼片段和文件信息

clear?all
clc
N=1000;
t1=0:333;
t2=0.1:sqrt(2):(0.1+332*sqrt(2));
t3=0.2:sqrt(5):(0.2+332*sqrt(5));
t=[t1?t2?t3];
clear?t1?t2?t3
t=sort(t);
K=201;
taumin=0;
taumax=10;
b=(taumax-taumin)/K;
D=zeros(1K);
for?i=1:K
????tauk(i)=(i-1/2)*(taumax-taumin)/K+taumin;
end
n=2;
while?n<=N
????m=n-1;
????while?m>=1
????????tau=t(n)-t(m);
????????if?(tau>taumin)&(tau<=taumax)
????????????for?k=1:K
????????????????if?(tau>(tauk(k)-b/2))&(tau<=(tauk(k)+b/2))
????????????????????D(k)=D(k)+1;????%exp(2*pi*t(n)*j/tau)
????????????????end
????????????end
????????elseif?tau>taumax
????????????break
????????else?
????????????;
????????end
????????m=m-1;
????end
????n=n+1;
end
plot(taukD)
axis([0?10?0?800])

?屬性????????????大小?????日期????時(shí)間???名稱
-----------?---------??----------?-----??----
?????目錄???????????0??2011-09-09?20:13??PRI_transform\
?????文件?????????696??2010-04-13?20:01??PRI_transform\autocorrelation_function.m
?????文件????????7339??2010-05-12?19:01??PRI_transform\data_generate.m
?????文件????????1549??2010-04-05?23:09??PRI_transform\improved2.m
?????文件????????2700??2010-04-19?12:51??PRI_transform\improved_thresholding.m
?????文件?????????960??2010-04-17?15:14??PRI_transform\pritransform.m
?????文件????????1280??2010-04-27?20:53??PRI_transform\pritransform2.m

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