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  • 大小: 7KB
    文件類型: .m
    金幣: 1
    下載: 1 次
    發布日期: 2021-06-07
  • 語言: Matlab
  • 標簽: CEC??TEST??MATLAB??

資源簡介

這是“A high-efficiency adaptive artificial bee colony algorithm using two strategies for continuous optimization”這篇論文中，28個CEC測試函數的MATLAB代碼，本人親自編寫，親自測試，跟論文中的效果一樣。在做群智能優化算法的同學們，可以直接拿去用了。

資源截圖

代碼片段和文件信息 

%?lb?is?the?lower?bound:?lb=[lb_1lb_2...lb_d]
%?up?is?the?uppper?bound:?ub=[ub_1ub_2...ub_d]
%?dim?is?the?number?of?variables?（dimension?of?the?problem）

function?[lbubdimfobj]?=?Get_Functions_details_28（F）


switch?F
????case?‘F1‘
????????fobj?=?@F1;
????????lb=-100;
????????ub=100;
????????dim=10;
????????
????case?‘F2‘
????????fobj?=?@F2;
????????lb=-100;
????????ub=100;
????????dim=10;
????????
????case?‘F3‘
????????fobj?=?@F3;
????????lb=-10;
????????ub=10;
????????dim=10;
????????
????case?‘F4‘
????????fobj?=?@F4;
????????lb=-10;
????????ub=10;
????????dim=10;
????????
????case?‘F5‘
????????fobj?=?@F5;
????????lb=-10;
????????ub=10;
????????dim=10;
????????
????case?‘F6‘
????????fobj?=?@F6;
????????lb=-100;
????????ub=100;
????????dim=10;
????????
????case?‘F7‘
????????fobj?=?@F7;
????????lb=-100;
????????ub=100;
????????dim=10;
????????
????case?‘F8‘
????????fobj?=?@F8;
????????lb=-1.28;
????????ub=1.28;
????????dim=10;
????????
????case?‘F9‘
????????fobj?=?@F9;
????????lb=-1.28;
????????ub=1.28;
????????dim=10;
????????
????case?‘F10‘
????????fobj?=?@F10;
????????lb=-10;
????????ub=10;
????????dim=10;
????????
????case?‘F11‘
????????fobj?=?@F11;
????????lb=-5.12;
????????ub=5.12;
????????dim=10;
????????
????case?‘F12‘
????????fobj?=?@F12;
????????lb=-5.12;
????????ub=5.12;
????????dim=10;
????????
????case?‘F13‘
????????fobj?=?@F13;
????????lb=-600;
????????ub=600;
????????dim=10;
????????
????case?‘F14‘
????????fobj?=?@F14;
????????lb=-500;
????????ub=500;
????????dim=10;
????????
????case?‘F15‘
????????fobj?=?@F15;
????????lb=-32;
????????ub=32;
????????dim=10;
????????
????case?‘F16‘
????????fobj?=?@F16;
????????lb=-50;
????????ub=50;
????????dim=10;
????????
????case?‘F17‘
????????fobj?=?@F17;
????????lb=-50;
????????ub=50;
????????dim=10;
????????
????case?‘F18‘
????????fobj?=?@F18;
????????lb=-10;
????????ub=10;
????????dim=10;
????????
????case?‘F19‘
????????fobj?=?@F19;
????????lb=-10;
????????ub=10;
????????dim=10;
????????
????case?‘F20‘
????????fobj?=?@F20;
????????lb=-0.5;
????????ub=0.5;
????????dim=10;
????????
????case?‘F21‘
????????fobj?=?@F21;
????????lb=-100;
????????ub=100;
????????dim=10;
????????
????case?‘F22‘
????????fobj?=?@F22;
????????lb=-5;
????????ub=5;
????????dim=10;
????????
????case?‘F23‘
????????fobj?=?@F23;
????????lb=0;
????????ub=pi;
????????dim=10;
????case?‘F24‘
????????fobj?=?@F24;
????????lb=-100;
????????ub=100;
????????dim=10;
????????
????case?‘F25‘
????????fobj?=?@F25;
????????lb=-5.12;
????????ub=5.12;
????????dim=10;
????case?‘F26‘
????????fobj?=?@F26;
????????lb=-600;
????????ub=600;
????????dim=10;
????case?‘F27‘
????????fobj?=?@F27;
????????lb=-32;
????????ub=32;
????????dim=10;
????case?‘F28‘
????????fobj?=?@F28;
????????lb=-10;
????????ub=10;
????????dim=10;
end

end

%?F1?Sphere?US

function?o?=?F1（x）
o=sum（x.^2）;
end

%?F2?Elliptic?UN

function?o?=?F2（x）
dim=size（x2）;
o=0;
for?i=1:dim
????o=o+10^（6*（i-1）/（dim-1））*（?x（1i）^2）
end
end

%?F3?SumSquares

function?o?=?F3（x）
dim=si

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