function?jpeg

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close?all;

%?==================
%?section?1.2?+?1.3
%?==================
%?the?following?use?of?the?function:????
%
%????plot_bases（?base_sizeresolutionplot_type?）
%
%?will?plot?the?64?wanted?bases.?I?will?use?“zero-padding“?for?increased?resolution
%?NOTE?THAT?THESE?ARE?THE?SAME?baseS?!
%?for?reference?I?plot?the?following?3?graphs:
%?a）?3D?plot?with?basic?resolution?（64?plots?of?8x8?pixels）?using?“surf“?function
%?b）?3D?plot?with?x20?resolution?（64?plots?of?160x160?pixels）?using?“mesh“?function
%?c）?2D?plot?with?x10?resolution?（64?plots?of?80x80?pixels）?using?“mesh“?function
%?d）?2D?plot?with?x10?resolution?（64?plots?of?80x80?pixels）?using?“imshow“?function
%
%?NOTE:?matrix?size?of?pictures?（b）（c）?and?（d）?can?support?higher?frequency?=?higher?bases
%???????but?I?am?not?asked?to?draw?these?（higher?bases）?in?this?section?!
%???????the?zero?padding?is?used?ONLY?for?resolution?increase?!
%
%?get?all?base?pictures?（3D?surface?figure）
plot_bases（?81‘surf3d‘?）;

%?get?all?base?pictures?（3D?surface?figure）?x20?resolution
plot_bases（?820‘mesh3d‘?）;

%?get?all?base?pictures?（2D?mesh?figure）?x10?resolution
plot_bases（?810‘mesh2d‘?）;???

%?get?all?base?pictures?（2D?mesh?figure）?x10?resolution
plot_bases（?810‘gray2d‘?）;???



%?==================
%?section?1.4?+?1.5
%?==================
%?for?each?picture?{‘0‘..‘9‘}?perform?a?2?dimensional?dct?on?8x8?blocks.
%?save?the?dct?inside?a?cell?of?the?size:?10?cells?of?128x128?matrix
%?show?for?each?picture?it‘s?dct?8x8?block?transform.

for?idx?=?0:9
???
???%?load?a?picture
???switch?idx
???case?{01}?input_image_128x128?=?im2double（?imread（?sprintf（?‘%d.tif‘idx?）‘tiff‘?）?）;
???otherwise?input_image_128x128?=?im2double（?imread（?sprintf（?‘%d.tif‘idx）‘jpeg‘?）?）;
???end???
???
???%?perform?DCT?in?2?dimension?over?blocks?of?8x8?in?the?given?picture
???dct_8x8_image_of_128x128{idx+1}?=?image_8x8_block_dct（?input_image_128x128?）;

???if?（mod（idx2）==0）
??????figure;
???end?????
???subplot（22mod（idx2）*2+1）;????????????
???imshow（input_image_128x128）;
???title（?sprintf（‘image?#%d‘idx）?）;
???subplot（22mod（idx2）*2+2）;?????????????
???imshow（dct_8x8_image_of_128x128{idx+1}）;
???title（?sprintf（‘8x8?DCT?of?image?#%d‘idx）?）;
end



%?==================
%?section?1.6
%?==================
%?do?statistics?on?the?cell?array?of?the?dct?transforms
%?create?a?matrix?of?8x8?that?will?describe?the?value?of?each?“dct-base“?
%?over?the?transform?of?