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單目視覺(jué)的位姿估算算法 matlab代碼 基于位姿估算正交迭代的算法,有test程序和主程序,test中可以比對(duì)估算的精度

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代碼片段和文件信息

function?[R?t?Qout?err2]?=?abskernel(P?Q?F?G?method)
%?ABSKERNEL?-??Absolute?orientation?kernel
%???ABSKERNEL?is?the?function?for?solving?the
%???intermediate?absolute?orientation?problems
%???in?the?inner?loop?of?the?OI?pose?estimation
%???algorithm
%
%???INPUTS:
%?????P?-?the?reference?point?set?arranged?as?a?3xn?matrix
%?????Q?-?the?point?set?obtained?by?transforming?P?with
%?????????some?pose?estimate?(typically?the?last?estimate)
%?????F?-?the?array?of?projection?matrices?arranged?as
%?????????a?3x3xn?array
%?????G?-?a?matrix?precomputed?for?calculating?t
%?????method?-?‘SVD‘??->?use?SVD?solution?for?rotation
%??????????????‘QTN‘?->?use?quaterion?solution?for?rotation
%
%
%???OUTPUTS:
%?????R?-?estimated?rotation?matrix
%?????t?-?estimated?translation?vector
%?????Qout?-?the?point?set?obtained?by?transforming?P?with
%?????????newest?pose?estimate
%?????err2?-?sum?of?squared?object-space?error?associated?
%?????????with?the?estimate

n?=?size(P2);

for?i?=?1:n
??Q(:i)?=?F(::i)*Q(:i);
end

%?compute?P‘?and?Q‘
pbar?=?sum(P2)/n;
qbar?=?sum(Q2)/n;
for?i?=?1:n
??P(:i)?=?P(:i)-pbar;
??Q(:i)?=?Q(:i)-qbar;
end

if?method?==?‘SVD‘?%?use?SVD?solution
??%?compute?M?matrix
??M(1:31:3)?=?0;
??for?i?=?1:n
????M?=?M+P(:i)*Q(:i).‘;
??end
??
??%?calculate?SVD?of?M
??[USV]?=?svd(M);
??
??%?compute?rotation?matrix?R
??R?=?V*(U.‘);
elseif?method?==?‘QTN‘?%?use?quaternion?solution
??%?compute?M?matrix
??A(1:41:4)?=?0;
??for?i?=?1:n
????A?=?A?+?qmatQ([1;Q(:i)]).‘*qmatW([1;P(:i)]);
??end
??
??%?Find?the?largest?eigenvalue?of?A?
??eigs_options.disp?=?0;
??[VD]?=?eigs(A?eye(size(A))?1?‘LM‘?eigs_options);
??
??%?compute?rotation?matrix?R?from?the?quaternion?that
??%?corresponds?to?the?largest?egienvalue?of?A
??R?=?quat2mat(V);
end

sum(1:31)?=?0;
for?i?=?1:n
??sum?=?sum?+?F(::i)*R*P(:i);
end
t?=?G*sum;

Qout?=?xform(P?R?t);

%?calculate?error
err2?=?0;
vec(1:31)?=?0;
for?i?=?1?:?n
??vec?=?(eye(3)-F(::i))*Qout(:i);
??err2?=?err2?+?dot(vecvec);
end

%?end?of?ABSKERNEL

?屬性????????????大小?????日期????時(shí)間???名稱(chēng)
-----------?---------??----------?-----??----

?????文件???????2104??2015-08-05?16:22??正交迭代OI算法\abskernel.m

?????文件????????716??1999-11-18?11:27??正交迭代OI算法\abspose.m

?????文件????????754??1999-11-18?11:27??正交迭代OI算法\euler2mat.m

?????文件???????1540??2015-08-11?11:10??正交迭代OI算法\ghtest.m

?????文件????????391??1999-11-18?11:27??正交迭代OI算法\mat2euler.m

?????文件????????390??1999-11-18?11:27??正交迭代OI算法\mat2rot.m

?????文件???????5907??2015-08-11?16:36??正交迭代OI算法\objpose.m

?????文件????????203??1999-11-25?08:42??正交迭代OI算法\qmatQ.m

?????文件????????205??1999-11-25?08:44??正交迭代OI算法\qmatW.m

?????文件????????293??1999-11-30?10:22??正交迭代OI算法\quat2mat.m

?????文件????????431??1999-11-18?11:27??正交迭代OI算法\randrotmat.m

?????文件????????406??1999-11-18?11:27??正交迭代OI算法\rot2mat.m

?????文件????????225??1999-11-20?02:49??正交迭代OI算法\xform.m

?????文件????????357??1999-11-20?02:49??正交迭代OI算法\xformproj.m

?????目錄??????????0??2015-08-13?19:00??正交迭代OI算法

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????????????????13922????????????????????15


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