lpcc=zeros（（s2-s1+1）12）;
j=1;
for?i=s1:s2
?????z=y（i:）;
?????a=lpc（z10）;
?????a=real（a（2:11））;
?????cc=lpc2lpcc（a）;
?????cc1=cc（2:13）;
?????lpcc（j:）=cc1‘;
?????j=j+1;
?end
?dlpcc=zeros（size（lpcc））;
for?i=3:size（lpcc1）-2;
?????dlpcc（i:）=-2*lpcc（i-2:）-lpcc（i-1:）+lpcc（i+1:）+2*lpcc（i+2:）;
end
dlpcc=dlpcc/10;
dlpcc=dlpcc（3:size（dlpcc1）-2:）;

?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----

?????文件????????365??2006-11-02?19:46??speakerrecognition\lpcc.m

?????文件????????563??2006-11-02?19:48??speakerrecognition\mfcc.m

?????文件????????497??2006-11-02?19:50??speakerrecognition\動態時間歸整.m

?????文件????????578??2006-11-02?19:49??speakerrecognition\預處理.m

?????目錄??????????0??2006-11-02?19:51??speakerrecognition

-----------?---------??----------?-----??----

?????????????????2221????????????????????6