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  • 大小: 3KB
    文件類型: .m
    金幣: 1
    下載: 0 次
    發(fā)布日期: 2021-06-16
  • 語言: Matlab
  • 標(biāo)簽: 端點(diǎn)檢測??

資源簡介

matlab 基于雙門限的端點(diǎn)檢測 小波分解,提取高頻系數(shù),計(jì)算能量,然后設(shè)定雙閾值實(shí)現(xiàn)檢測

資源截圖

代碼片段和文件信息

clc;close?all;clear?all;
signal=wavread(‘G:\abonrmalsounddetect\VOICE003.wav‘);
%signal1=flipud(signal);
framelen=2048;framewap=1024;
temp=enframe(signalframelenframewap);???????????%信號(hào)分幀
framelen1=512;framewap1=8;
point=size(temp);
for?i=1:point(1)
????[cl]=wavedec(temp(i1:2048)3‘db6‘);????????%小波變換
????coefficent=c(1051:2079);??????????????????????%高頻系數(shù)提取
????
????energywav(i)=sum(abs(coefficent)2);??????????%直接由小波系數(shù)計(jì)算能量--1
????
????temp1=enframe(coefficentframelen1framewap1);%二次分幀求取平均能量--2
????for?j=1:size(temp1)
?????????energy(j)=sum(abs(temp1(j))2);??????????%2的分能量,3的能量
%?????????energy(j)=abs(temp1(j));
????end
????energycoe(i)=mean(energy);????????????????????
????temp2=enframe(coefficentframelen164);???????%二次分幀求取平均能量--3
????for?j=1:size(temp2)
????????energy(j)=sum(abs(temp2(j))2);???????????%3的能量
%???????????energy(j)=abs(temp2(j));?
????end
????energyfra(i)=mean(energy);??
????for?n=1:size(temp2)???????????????????????????%3--異常檢測
????????
????????if?energy(n)-energyfra(i)>energy(n)*0.7?
????????????resultfra(i)=1;
????????else?resultfra(i)=0;
????????end
????end
end
%?energymean=medfilt1(energymean3);
for?i=1:point(1)-1
????throsholdcoe(i)=0;throsholdwav(i)=0;
????if?i>2
????????throsholdwav(i)=1.15*(energywav

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