資源簡介
有ARMA的功率譜估計的代碼,在MATLAB上面運行。可以得到最終估計的結果圖,以及與真實值的比較

代碼片段和文件信息
function?[a?e]?=?AR(x?p)
%?AR自協方差算法譜估計,輸入采樣數據x,預測階數p,輸出模型傳輸函數系數a
%?返回H(z)=e/(1+A(z))中的A,e是sigma^2
N?=?length(x);
A?=?zeros(p?N-p);
for?n=1:p
????for?m=1:N-p
????????A(n?m)?=?x(p-n+m);??%A‘
????end
end
xf?=?x(p+1:N);
[V1?D1]?=?eig(A*A‘);
a?=?-1*pinv(A‘)*xf;
e?=?(xf‘*xf+a‘*A*xf)/(N-p);
%test
%?clear;
%?close?all;
%?a?=?[1?-1.3817?1.5632?-0.8843?0.4096];
%?b?=?[1?0.3544?0.3508?0.1736?0.2401];
%?x?=?xx(a?b?200?256);
%?[coa?coe]?=?AR(x?4);
%?coa?=?[1;coa];
%?cob?=?sqrt(coe);
%?[wP]?=?spectrum(coa?cob?128);
%?plot(w?P);
?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????目錄???????????0??2019-03-23?21:45??source\
?????文件?????????607??2006-05-09?16:33??source\AR.m
?????文件?????????685??2006-05-10?19:19??source\AR2.m
?????文件?????????215??2006-05-09?16:33??source\ARMA.m
?????文件?????????495??2006-05-10?19:11??source\MA.m
?????文件????????4664??2019-03-23?21:14??source\main1.m
?????文件????????7147??2006-05-10?20:17??source\main2.m
?????文件?????????248??2006-05-09?17:14??source\Periodic.m
?????文件?????????276??2006-05-10?20:36??source\polyzero.m
?????文件?????????242??2006-05-10?20:03??source\Rxx.m
?????文件?????????598??2006-05-09?10:55??source\spectrum.m
?????文件????????2196??2019-03-23?21:14??source\xdata.mat
?????文件?????????393??2006-05-10?19:48??source\xx.m
?????文件?????????502??2006-05-10?18:44??source\YuleWalker.m
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