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資源簡介

本次上傳的IEEE 33節點配電網是根據M. A. Kashem等發表的《A novel method for loss minimization in distribution networks》進行搭建MATLAB模型,此模型適應于進行配電網潮流計算,不適用于配電網故障定位,若是想要研究故障定位方向的,請找我之前發的一個資源。

資源截圖

代碼片段和文件信息

clear?all;
Bus=[100???;
2100?60;
39040;
412080;
56030;
66020;
7?200?100?;
8200??100?;
9?60?20;
1060?20;
114530;
1260?35;
1360?35;
1412080;
1560?10;
1660?20;
1760?20;
1890?40;
1990?40;
2090?40;
2190?40;
2290?40;?
2390?40;?
24420?200;
25420?200?;
2660?25;
2760?25;
2860?20;
29120?70;
30200600?;
31150?70;
32210?100?;
336040;
];
Branch=[1?1?2?0.09220.0407;
??2?2?3?0.49300.2511;
??3?3?4?0.36600.1864;
4?4?5?0.38110.1941;
5?5?6?0.81900.7070;
6?6?7?0.18720.6188;
7?7?8?0.71440.2351;
8?8?9?1.03000.7400;
9?9?101.04400.7400;
1010110.19660.065;
1111120.37440.1238;
1212131.46801.1550;
1313140.54160.7129;
1414150.59100.5260;
1515160.74630.5450;
1616171.28901.7210;
1717180.73200.5740;
182?190.16400.1565;
1919201.50421.3554;
2020210.40950.4784;
2121220.70890.9373;
223?230.45120.3083;
2323240.89800.7091;
2424250.89600.7011;
256?260.20300.1034;
2626270.28420.1447;
2727281.05900.9337;
2828290.80420.7006;
2929300.50750.2585;
3030310.97440.9630;
3131320.31050.3619;
3232330.34100.5302;
?];
[busnumrow]=size(Bus);
[branchnumrow]=size(Branch);
soubus=Branch(:2);
mobus=Branch(:3);
Vbus=ones(busnum1);
Vbus(:1)=12.66;
Vbus1=Vbus;
Ploss=zeros(busnum1);
Qloss=zeros(busnum1);
e=1;
k=0;
Branch1=Branch;
n=1;
while?~isempty(Branch1)
m=1;
[srow]=size(Branch1);
while?s>0
t=find(Branch1(:2)==?Branch1(s3));
if?isempty(t)
T1(n:)=?Branch1(s:);
n=n+1;
else
T2(m:)=?Branch1(s:);
m=m+1;
end;
s=s-1;
end;
Branch1=T2;
T2=[];
end;
while?e>1.0e-05
P=zeros(busnum1);
Q=zeros(busnum1);
for?s=1:branchnum
i=T1(s2);
j=T1(s3);
R=T1(s4);
X=T1(s5);
Pload=Bus(j2);
Qload=Bus(j3);
II=((Pload+P(j))^2+(Qload+Q(j))^2)/(Vbus(j)^2*1000);
Ploss(ij)=II*R;
Qloss(ij)=II*X;
P(ij)=Pload+Ploss(ij)+P(j);
Q(ij)=Qload+Ploss(ij)+Q(j);
P(i)=P(i)+P(ij);
Q(i)=Q(i)+Q(ij);
end;
for?s=branchnum:-1:1
i=T1(s2);
j=T1(s3);
R=T1(s4);
X=T1(s5);
Vbus(j)=(Vbus(i)-(P(ij)*R+Q(ij)*X)/(Vbus(i)*1000))^2+((P(ij)*X-Q(ij)*R)/(Vbus(i)*1000))^2;
Vbus(j)=sqrt(Vbus(j));
end;
e=max(abs(Vbus1-Vbus));
Vbus1=Vbus;
k=k+1;
end


?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----

?????文件??????28504??2019-08-22?16:37??IEEE?33節點配電網\IEEE?33節點配電網.rar

?????文件??????32050??2019-11-26?15:38??IEEE?33節點配電網\ieee33.slx

?????文件??????27788??2019-08-21?17:20??IEEE?33節點配電網\ieee33.slx.r2012b

?????文件?????650066??2019-11-26?15:33??IEEE?33節點配電網\IEEE33配電網系統.pdf

?????文件???????2315??2019-08-21?17:27??IEEE?33節點配電網\mieee33.m

?????目錄??????????0??2019-11-26?15:40??IEEE?33節點配電網

-----------?---------??----------?-----??----

???????????????740723????????????????????6


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