資源簡介
數字通信基礎實驗二,利用MATLAB對QPSK誤碼率進行分析分析作圖,詳細注釋!

代碼片段和文件信息
function[pbps]=cm_sm32(SNRindB)
N=10000;
E=1;
SNR=10^(SNRindB/10);
sgma=sqrt(E/SNR)/2;
s00=[1?0];
s01=[0?1];
s11=[-1?0];
s10=[0?-1];
for?i=1:N
????temp=rand;
????if?(temp<0.25)
????????dsource1(i)=0;
????????dsource2(i)=0;
????elseif?(temp<0.5)
????????dsource1(i)=0;
????????dsource2(i)=1;
????elseif?(temp<0.75)
????????dsource1(i)=1;
????????dsource2(i)=0;
????else?
????????dsource1(i)=1;
????????dsource2(i)=1;
????end;
end;
numofsymbolerror=0;
numofbiterror=0;
for?i=1:N
????n=sgma*randn(size(s00));
????if((dsource1(i)==0)&(dsource2(i)==0))
????????r=s00+n;
????elseif((dsource1(i)==0)&(dsource2(i)==1))
????????r=s01+n;
????elseif((dsource1(i)==1)&(dsource2(i)==0))
????????r=s10+n;
????else
????????r=s11+n;
end;
c00=dot(rs00);
c01=dot(rs01);
c10=dot(rs10);
c11=dot(rs11);
c_max=max([c00?c01?c10?c11]);
if?(c00==c_max)
????decis1=0;decis2=0;
????elseif(c01==c_max)
????????decis1=0;decis2=1;
????elseif(c10==c_max)
????????decis1=1;decis2=0;
????else
????????decis1=1;decis2=1;
end;
symbolerror=0;
if(decis1~=dsource1(i))
????numofbiterror=numofbiterror+1;
????symbolerror=1;
end;
if(decis2~=dsource2(i))
????numofbiterror=numofbiterror+1;
????symbolerror=1;
end;
if(symbolerror==1)
????numofsymbolerror=numofsymbolerror+1;
end;
end;
ps=numofsymbolerror/N;
pb=numofbiterror/(2*N);
?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????目錄???????????0??2019-07-14?11:33??QPSK誤碼率分析作圖\
?????文件????????1360??2019-06-20?21:27??QPSK誤碼率分析作圖\cm_sm32.m
?????文件?????????513??2019-06-20?21:30??QPSK誤碼率分析作圖\Main.m
?????文件??????????47??2019-06-20?21:25??QPSK誤碼率分析作圖\Qfunct.m
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