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基于matlab的用于銑削動力學建模的穩定性葉瓣圖分析-stablity lobe

代碼片段和文件信息
clear
%?parameters
N?=?2;??????????????%?number?of?teeth
Kt?=?6e8;???????????%?tangential?cutting?force?coef?cient(N/m2)
Kn?=?2e8;???????????%?normal?cutting?force?coef?cient(N/m2)
w0?=?922*2*pi;?????%?angular?natural?frequency?(rad/s)
zeta?=?0.011;??????%?relative?damping?(1)
m_t?=?0.03993;?????%?mass?(kg)
aD?=?0.05;??????????%?radial?depth?of?cut
up_or_down?=?-1;???%?1:?up-milling??1:?down-milling
if?up_or_down?==?1?%?up-milling
???fist?=?0;????????%?start?angle
???fiex?=?acos(1?-?2*aD);?%?exit?angle
elseif?up_or_down?==?-1?%?down-milling
???fist?=?acos(2*aD?-?1);?%?start?angle
???fiex?=?pi;?%?exit?angle
end
stx?=?400;?%?steps?of?spindle?speed
sty?=?200;?%?steps?of?depth?of?cut
w_st?=?0e-3;?%?starting?depth?of?cut?(m)
w_fi?=?10e-3;?%??nal?depth?of?cut?(m)
o_st?=?5e3;?%?starting?spindle?speed?(rpm)
o_fi?=?25e3;?%??nal?spindle?speed?(rpm)
%?computational?parameters
k?=?40;?%?number?of?discretization?interval?over?one?period
intk?=?20;?%?number?of?numerical?integration?steps?for?Equation?(37)
m?=?k;?%?since?time?delay?=?time?period
wa?=1/2;?%?since?time?delay?=?time?period
wb?=1/2;?%?since?time?delay?=?time?period
D?=?zeros(m?+?2?m?+?2);?%?matrix?D
d?=?ones(m?+?1?1);
d(1?:?2)?=?0;
D?=?D?+?diag(d?-1);
D(31)?=?1;
%?numerical?integration?of?speci?c?cutting?force?coef?cient?according?to?Equation?(37)
for?i?=?1?:?k
????dtr?=?2*pi/N/k;?%t?if?=?2?/N
????h_i(i)?=?0;
????for?j?=?1?:?N?%?loop?for?tooth?j
????????for?h?=?1?:?intk?%?loop?for?numerical?integration?of????h
?????????????fi(h)?=?i*dtr?+?(?j?-?1)*2*pi/N?+?h*dtr/intk;
?????????????if(fi(h)?>=?fist)*(fi(h)?<=?fiex)
?????????????????g(h)?=?1;?%?tooth?is?in?the?cut
?????????????else
?????????????????g(h)?=?0;?%?tooth?is?out?of?cut
?????????????end
????????end
????????h_i(i)?=?h_i(i)?+?sum(g.*(Kt.*cos(fi)?+?Kn.*sin(fi)).*sin(fi))/intk;
????end
end
%?start?of?computation
for?x?=?1?:?stx?+?1?%?loop?for?spindle?speeds
????o?=?o_st?+?(x?-?1)*(o_fi?-?o_st)/stx;?%?spindle?speed
????tau?=?60/o/N;?%?time?delay
????dt?=?tau/(m);?%?time?step
????for?y?=?1?:?sty?+?1?%?loop?for?depth?of?cuts
????????w?=?w_st?+?(y?-?1)*(w_fi?-?w_st)/sty;?%?depth?of?cut
????????%?construct?transition?matrix?Fi
????????Fi?=?eye(m?+?2?m?+?2);
????????for?i?=?1?:?m
????????????A?=?zeros(2?2);?%?matrix?Ai
????????????A(12)?=?1;
????????????A(21)?=?-w0^2?-?h_i(i)*w/m_t;
????????????A(22)?=?-2*zeta*w0;
????????????B?=?zeros(2?2);?%?matrix?Bi
????????????B(21)?=?h_i(i)*w/m_t;
????????????P?=?expm(A*dt);?%?matrix?Pi
????????????R?=?(expm(A*dt)?-?eye(2))*inv(A)*B;?%?matrix?Ri
????????????D(1?:?2?1?:?2)?=?P;
????????????D(1?:?2?m?+?1)?=?wa*R(1?:?2?1?:?1);
????????????D(1?:?2?m?+?2)?=?wb*R(1?:?2?1?:?1);
????????????Fi?=?D*Fi;?%?transition?matrix
????????end
????ss(xy)?=?o;?%?matrix?of?spindle?speeds
????dc(xy)?=?w;?%?matrix?of?depth?of?cuts
????ei(xy)?=?max(abs(eig(Fi)));?%?matrix?of?eigenvalues
????end
stx?+?1?-?x
end
figure
contour(ssdcei[
?屬性????????????大小?????日期????時間???名稱
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?????文件????????3100??2013-03-19?15:38??lobe_semi.m
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