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資源簡介

結合一個題目演示了如何自編代碼實現用多項式函數和指數函數作為基函數來實現最小二乘擬合,函數文件獨立,便于移植,便于推廣,題目附有解答,題目來自西工大數值計算方法作業。采用MATLAB實現。

資源截圖

代碼片段和文件信息

k=1:10;
t=(k-1)/10;
y=erf(t);

fun0=@(x)1;
fun1=@(x)x;
fun2=@(x)x*x;
fun3=@(x)power(x3);
fun4=@(x)power(x4);
fun5=@(x)power(x5);
fun6=@(x)power(x6);
fun7=@(x)power(x7);
fun8=@(x)power(x8);
fun9=@(x)power(x9);
fun10=@(x)power(x10);
fun11=@(x)exp(-x*x);
fun12=@(x)exp(-x*x)/(1+x);
fun13=@(x)exp(-x*x)/(1+x)/(1+x);
fun14=@(x)exp(-x*x)/(1+x)/(1+x)/(1+x);

phi1={fun0fun1};
phi2={fun0fun1fun2};
phi3={fun0fun1fun2fun3};
phi4={fun0fun1fun2fun3fun4};
phi5={fun0fun1fun2fun3fun4fun5};
phi6={fun0fun1fun2fun3fun4fun5fun6};
phi7={fun0fun1fun2fun3fun4fun5fun6fun7};
phi8={fun0fun1fun2fun3fun4fun5fun6fun7fun8};
phi9={fun0fun1fun2fun3fun4fun5fun6fun7fun8fun9};
phi10={fun0fun1fun2fun3fun4fun5fun6fun7fun8fun9fun10};

phi11={fun1fun3};
phi12={fun1fun3fun5};
phi13={fun1fun3fun5fun7};
phi14={fun1fun3fun5fun7fun9};

phi15={fun0fun11fun12fun13fun14};

err=zeros(151);
[~err(1)]=leastsquareEstimation(phi1yt);
[~err(2)]=leastsquareEstimation(phi2yt);
[~err(3)]=leastsquareEstimation(phi3yt);
[~err(4)]=leastsquareEstimation(phi4yt);
[~err(5)]=leastsquareEstimation(phi5yt);
[~err(6)]=leastsquareEstimation(phi6yt);
[~err(7)]=leastsquareEstimation(phi7yt);
[~err(8)]=leastsquareEstimation(phi8yt);
[~err(9)]=leastsquareEstimation(phi9yt);
[~err(10)]=leastsquareEstimation(phi10yt);
[~err(11)]=leastsquareEstimation(phi11yt);
[~err(12)]=leastsquareEstimation(phi12yt);
[~err(13)]=leastsquareEstimation(phi13yt);
[~err(14)]=leastsquareEstimation(phi14yt);
[~err(15)]=leastsquareEstimation(phi15yt);

format?long
err

?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????文件????????1677??2017-11-10?10:14??最小二乘函數擬合\Ex3_1.m
?????文件?????????638??2017-11-10?09:52??最小二乘函數擬合\leastsquareEstimation.m
?????文件???????24561??2018-12-15?14:13??最小二乘函數擬合\示例題目.docx

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