function?I=ComSimpson（abn）
n=2;
h=（b-a）/2;
I1=0;
I2=（f（a）+f（b））/h;
eps=1.0e-4;
while（abs（I2-I1）>eps）
????n=n+1;
????h=（b-a）/n;
????I1=I2;
????I2=0;
????for（i=0:n-1）
????????x=a+h*i;
????????x1=x+h;
????????I2=I2+h/6*（f（x）+4*f（（x+x1）/2）+f（x1））;
????end
end
I=I2

?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????目錄???????????0??2019-07-05?19:51??matlab數(shù)據(jù)分析代碼合集\
?????目錄???????????0??2019-06-22?12:36??matlab數(shù)據(jù)分析代碼合集\ComSimpson\
?????文件?????????281??2019-06-22?12:38??matlab數(shù)據(jù)分析代碼合集\ComSimpson\ComSimpson.m
?????文件??????????28??2019-06-22?10:32??matlab數(shù)據(jù)分析代碼合集\ComSimpson\f.m
?????目錄???????????0??2019-06-22?12:29??matlab數(shù)據(jù)分析代碼合集\ComTrapezoidal\
?????文件?????????228??2019-06-22?12:23??matlab數(shù)據(jù)分析代碼合集\ComTrapezoidal\ComTrapezoidal.m
?????文件??????????28??2019-06-22?10:32??matlab數(shù)據(jù)分析代碼合集\ComTrapezoidal\f.m
?????目錄???????????0??2019-06-22?19:57??matlab數(shù)據(jù)分析代碼合集\Euler\
?????文件?????????260??2019-06-22?20:32??matlab數(shù)據(jù)分析代碼合集\Euler\Euler.m
?????文件??????????37??2019-06-22?20:29??matlab數(shù)據(jù)分析代碼合集\Euler\f.m
?????目錄???????????0??2019-06-22?19:05??matlab數(shù)據(jù)分析代碼合集\HalfInterval\
?????文件?????????751??2019-06-22?19:09??matlab數(shù)據(jù)分析代碼合集\HalfInterval\HalfInterval.m
?????目錄???????????0??2019-06-22?19:38??matlab數(shù)據(jù)分析代碼合集\NewtonRootl\
?????文件??????????30??2019-06-22?19:36??matlab數(shù)據(jù)分析代碼合集\NewtonRootl\df.m
?????文件??????????33??2019-06-22?19:29??matlab數(shù)據(jù)分析代碼合集\NewtonRootl\f.m
?????文件?????????241??2019-06-22?19:35??matlab數(shù)據(jù)分析代碼合集\NewtonRootl\NewtonRootl.m
?????目錄???????????0??2019-06-22?21:47??matlab數(shù)據(jù)分析代碼合集\Runge_Kutta4\
?????文件?????????359??2019-06-22?20:55??matlab數(shù)據(jù)分析代碼合集\Runge_Kutta4\Funval.m
?????文件?????????391??2019-06-22?21:46??matlab數(shù)據(jù)分析代碼合集\Runge_Kutta4\Runge_Kutta4.m
?????文件??????166910??2019-06-24?23:13??matlab數(shù)據(jù)分析代碼合集\代碼示例及數(shù)據(jù)分析.docx