function?analysis（image）
c=imread（image）;
b=c（:2:end）;
c=c（:1:end-1）;
temp=randperm（numel（c）5000）;
b=b（:）;
c=c（:）;
b=b（temp）;c=c（temp）;
plot（cb‘*‘）;
title（‘Correlation?of?plain?image‘）;
xlabel（‘pixel?value?on?location?（xy）‘）;
ylabel（‘pixel?value?on?location?（x+1y）‘）;??%請于此處斷點之后在繼續(xù)另外兩部分的判斷，這樣隨機數(shù)統(tǒng)一，或者在randperm自行添加隨機數(shù)參數(shù)
%?Horizontal=corr2（c（:1:end-1）c（:2:end:））;
%?Vertical=corr2（c（1:end-1:）c（2:end:））;
%?Diagonal=corr2（c（2:end1:end-1）c（1:end-12:end））????%只取一個對角

?屬性????????????大小?????日期????時間???名稱
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?????文件????????542??2014-12-29?11:14??Image?encryption\analysis.m

?????文件???????1776??2014-12-19?23:37??Image?encryption\decryption.m

?????文件???????3993??2014-12-27?16:11??Image?encryption\decryption2.m

?????文件??????66614??2014-12-27?15:27??Image?encryption\de_lena（change?d）.bmp

?????文件??????66614??2014-12-27?15:47??Image?encryption\de_lena（change?q）.bmp

?????文件??????66614??2014-12-27?15:45??Image?encryption\de_lena（change?y1）.bmp

?????文件???????1940??2014-12-27?16:07??Image?encryption\encryption.m

?????文件???????4516??2015-01-22?13:17??Image?encryption\encryption2.m

?????文件?????866772??2014-10-01?20:01??Image?encryption\Image?encryption?algorithm?with?compound?chaotic?maps.pdf

?????文件??????66614??2014-12-13?15:23??Image?encryption\lena.bmp

?????文件??????66614??2014-12-20?22:41??Image?encryption\lena1.bmp

?????文件??????66614??2014-12-20?23:18??Image?encryption\lena2.bmp

?????文件???????1925??2014-12-13?14:20??Image?encryption\manualhist.m

?????文件????????222??2014-12-27?15:09??Image?encryption\NPCR.m

?????文件?????263222??2014-12-27?16:05??Image?encryption\testmap.bmp

?????文件?????263222??2014-12-27?16:06??Image?encryption\testmap1.bmp

?????文件?????263222??2014-12-27?16:10??Image?encryption\testmap2.bmp

?????文件????????550??2015-01-08?16:58??Image?encryption\try_this.m

?????文件????????199??2014-12-29?11:19??Image?encryption\UACI.m

?????目錄??????????0??2015-07-01?09:50??Image?encryption

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??????????????2071785????????????????????20