function?vHat?=?decodeBitFlipping（rx?H?iteration）
%?Hard-decision/bit?flipping?sum?product?algorithm?LDPC?decoder
%??rx????????:?Received?signal?vector?（column?vector）
%??H?????????:?LDPC?matrix
%??iteration?:?Number?of?iteration
%??vHat??????:?Decoded?vector?（0/1）?

[M?N]?=?size（H）;
%?Prior?hard-decision
ci?=?0.5*（sign（rx‘）?+?1）;
%?Initialization
rji?=?zeros（M?N）;
%?Asscociate?the?ci?matrix?with?non-zero?elements?of?H
qij?=?H.*repmat（ci?M?1）;?
%?Iteration
for?n?=?1:iteration???
???fprintf（‘Iteration?:?%d\n‘?n）;???
???%?-----?Horizontal?step?-----
???for?i?=?1:M??????
??????%?Find?non-zeros?in?the?column
??????c1?=?find（H（i?:））;??????
??????%?Get?the?summation?of?qij\c1（k）????????
??????for?k?=?1:length（c1）
?????????rji（i?c1（k））?=?mod（sum（qij（i?c1））?+?qij（i?c1（k））?2）;?????????
??????end?%?for?k??????
???end?%?for?i
???
???%?------?Vertical?step?------
???for?j?=?1:N
??????%?Find?non-zero?in?the?row
??????r1?=?find（H（:?j））;??????
??????%?Number?of?1s?in?a?row
??????numOfOnes?=?length（find（rji（r1?j）））;??????
??????for?k?=?1:length（r1）?
?????????%?Update?qij?set?‘1‘?for?majority?of?1s?else?‘0‘?excluding?r1（k）
?????????if?numOfOnes?+?ci（j）?>=?length（r1）?-?numOfOnes?+?rji（r1（k）?j）
????????????qij（r1（k）?j）?=?1;
?????????else
????????????qij（r1（k）?j）?=?0;
?????????end??????????
??????end?%?for?k??????
??????%?Bit?decoding
??????if?numOfOnes?+?ci（j）?>=?length（r1）?-?numOfOnes
?????????vHat（j）?=?1;
??????else
?????????vHat（j）?=?0;
??????end?????????????
???end?%?for?j???
end?%?for?n

?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????目錄???????????0??2018-10-10?11:04??源碼\
?????文件?????1340928??2013-05-06?10:09??源碼\低密度奇偶校驗碼（LDPC）的編碼與解碼__最終版給客戶.doc
?????目錄???????????0??2017-01-25?14:00??源碼\程序\
?????文件?????1193984??2013-04-01?15:58??源碼\程序.doc
?????文件????????1565??2013-04-01?20:51??源碼\程序\decodeBitFlip.m
?????文件????????1744??2013-04-01?20:51??源碼\程序\main1.m
?????文件????????1948??2013-04-01?20:51??源碼\程序\main2.m
?????文件????????1897??2013-04-01?20:51??源碼\程序\main3.m
?????文件????????1937??2013-04-01?20:51??源碼\程序\main4.m
?????文件????????3389??2013-04-01?20:51??源碼\程序\makeLdpc.m
?????文件????????3740??2013-04-01?20:51??源碼\程序\makeParityChk.m
?????目錄???????????0??2018-10-10?11:04??演示\
?????文件?????2706511??2013-04-01?15:32??演示\ldpc編解碼的仿真.lxe
?????文件??????741751??2013-03-18?22:01??演示\基于MATLAB的低密度奇偶校驗碼（LDPC）編碼與解碼仿真.pdf
?????文件?????1534475??2013-04-01?20:22??演示\附代碼.lxe
?????目錄???????????0??2018-10-10?11:02??需求\
?????文件???????16896??2013-02-18?21:49??需求\項目要求說明書低版本.doc