資源簡(jiǎn)介
線(xiàn)性最小均方誤差估計(jì)LMMSE的matlab算法
代碼片段和文件信息
%**********File:系統(tǒng)辨識(shí)******************
clear?all
SNR_DB=[0:1:12];
sum=1000;
%********************產(chǎn)生QPSK信號(hào)***********************
data=randsrc(sum2[0?1]);
[a1b1]=find(data(:1)==0&data(:2)==0);
message(a1)=(-1-j)*sqrt(1/2);
[a2b2]=find(data(:1)==0&data(:2)==1);
message(a2)=(-1+j)*sqrt(1/2);
[a3b3]=find(data(:1)==1&data(:2)==0);
message(a3)=(1-j)*sqrt(1/2);
[a4b4]=find(data(:1)==1&data(:2)==1);
message(a4)=(1+j)*sqrt(1/2);
x=message;
%scatterplot(x)
h=[0.04-0.050.07-0.21-0.50.720.3600.210.030.07];?
d=conv(xh);
%scatterplot(d);
d=awgn(d20);%疊加高斯白噪聲?信噪比為50dB
%scatterplot(d);
%*******************系統(tǒng)辨識(shí)(LMS算法)***********************
N=13;%濾波器長(zhǎng)度
umax=2/(N*mean((abs(x)).^2));%步長(zhǎng)應(yīng)小于umax,計(jì)算出umax=0.13333
u=0.06;%取u=0.06
W=zeros(1N);
e=zeros(1su
?屬性????????????大小?????日期????時(shí)間???名稱(chēng)
-----------?---------??----------?-----??----
?????文件???????1759??2010-12-16?22:26??LMMSE.m
-----------?---------??----------?-----??----
?????????????????1759????????????????????1
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