資源簡介
文件包含Clarke和Jakes信道模型詳細的理論推導(dǎo)與區(qū)別,并附有完整代碼,可以清晰認識兩種常見無線模型。
代碼片段和文件信息
%?plot?Clark?channel?model
clear
clc
fm=100;?????%?最大Doppler
ts_mu=50;???%?持續(xù)時間
scale=1e-6;
ts=ts_mu*scale;?%采樣時間
fs=1/ts;????%?sample?frequency
Nd=1e6;?????%?采樣數(shù)
%generat?channel?information
[hNfftNifftDoppler_coeff]=Clarke_model(fmfsNd);
subplot(211)
plot([1:Nd]*ts10*log10(abs(h)));
str=sprintf(‘channel?model?by?Clarke?with?fm=%d[Hz]Ts=%d[mus]‘fmts_mu);
title(str);
%?信道包絡(luò)
subplot(223)
hist(abs(h)50);
%?信道相位
subplot(224)
hist(angle(h)50);
????????????
?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????目錄???????????0??2014-05-29?21:12??Clake?and?Jakes?channel\
?????目錄???????????0??2014-05-29?16:50??Clake?and?Jakes?channel\Clarke\
?????文件??????194936??2014-05-29?21:02??Clake?and?Jakes?channel\Clarke?Model?and?Jakes?model?analysis.docx
?????文件?????????511??2014-05-29?14:33??Clake?and?Jakes?channel\Clarke\Clarke.m
?????文件?????????939??2014-05-29?14:27??Clake?and?Jakes?channel\Clarke\Clarke_model.m
?????文件?????????409??2014-05-29?14:32??Clake?and?Jakes?channel\Clarke\Doppler.m
?????目錄???????????0??2014-05-29?16:53??Clake?and?Jakes?channel\Jakes\
?????文件????????1258??2014-05-29?17:23??Clake?and?Jakes?channel\Jakes\Jakes.asv
?????文件????????1216??2014-05-29?17:29??Clake?and?Jakes?channel\Jakes\Jakes.m
?????文件?????????809??2014-05-29?16:50??Clake?and?Jakes?channel\Jakes\Jakes_model.m
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