資源簡介
SAR成像BP算法,對點目標進行清晰雷達成像
代碼片段和文件信息
clear?all;
clc;
clear;
fmin=8e9;?fmax=12e9;
c=3e8;?M=901;
kmin=2*fmin/c;
B=2*(fmax-fmin)/c;
f_step=fmax-fmin/M-1;
R0=10;
R_v=1.5;
rx1=-0.4;
rx2=36;
rx3=0;
rx4=0.9;
rx5=0.3;
N=161;
angle_step=0.1;
for?n=1:N;
????sita=(n-(N+1)/2)*angle_step*pi/180;
????R1(1n)=sqrt(R0^2+rx1^2-2*R0*rx1*cos(sita+pi/2));
????R2(1n)=sqrt(R0^2+rx2^2-2*R0*rx2*cos(sita+pi/2));
????R3(1n)=sqrt(R0^2+rx3^2-2*R0*rx3*cos(sita+pi/4));
????R4(1n)=sqrt(R0^2+rx4^2-2*R0*rx4*cos(sita));
????R5(1n)=sqrt(R0^2+rx5^2-2*R0*rx5*cos(sita+pi/4));
end
for?m=1:M
????k=2*pi*(8e9+(m-1)*f_step)/c;
%?????E(1:Nm)=exp(-2j*k*(R1(1:)))./R0+exp(-2j*k*(R2(1:)))./R0+exp(-2j*k*(R3(1:)))./R0+exp(-2j*k*(R4(1:)))./R0+exp(-2j*k*(R5(1:)))./R0;
?%????E(1:Nm)=exp(-2j*k*(R1(1:)))./R1(1:);
?????E(1:Nm)=exp(-
?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????文件????????2221??2014-01-03?14:18??BP算法\FourDot.m
?????文件????????2929??2014-04-24?18:22??BP算法\imaging.m
?????目錄???????????0??2014-04-26?21:56??BP算法\
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