function[histLBPMatLBPMatLBP_MB]=getMBLBPFea（IblockSize）
if?nargin<2
????blockSize=1;
end
[mn]=size（I）;
mSub=floor（m/blockSize）;
nSub=floor（n/blockSize）;%?mSub，nSub是逼近m/blockSize的最小整數

mRem=mod（mblockSize）;
nRem=mod（nblockSize）;?%取余運算
mRem=round（mRem/2）;
nRem=round（nRem/2）;

I_MB=zeros（mSubnSub）;
for?ii=1:mSub
????for?jj=1:nSub
????????I_center=I（1+mRem:mRem+mSub*blockSize1+nRem:nRem+nSub*blockSize）;
????????SubRgn?=?I_center（?（ii-1）*blockSize+1?:ii*blockSize?（jj-1）*?blockSize+1:jj*blockSize?）;
????????I_MB（iijj）=mean（SubRgn（:））;
????end
end
%剩下的任務就是對分塊矩陣的特征
rad=2;
if（mSub<=2*rad）||（nSub<=2*rad）;
????error（‘I?is?too?small?to?conputer?LBP?feature!‘）;
end

MatLBP_MB=zeros（mSub-2*radnSub-2*rad）;
%讀入LBP映射
load?LBPMap.mat;

for?ii=1+rad:mSub-rad
????fo

?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----

?????文件???????7854??2012-05-14?20:02??LBP（修改版）\C01-1.bmp

?????文件???????7854??2012-05-14?20:02??LBP（修改版）\C02-1.bmp

?????文件???????6550??2012-05-14?20:02??LBP（修改版）\C03-1.bmp

?????文件???????9954??2012-05-14?20:02??LBP（修改版）\C04-1.bmp

?????文件???????2912??2012-05-14?20:43??LBP（修改版）\getMBLBPFea.asv

?????文件???????2908??2012-05-14?21:34??LBP（修改版）\getMBLBPFea.m

?????文件????????407??2012-05-14?20:02??LBP（修改版）\IsUniform.m

?????文件????????290??2012-05-14?21:53??LBP（修改版）\LBPMap.mat

?????文件??????28956??2012-05-14?21:42??LBP（修改版）\LBP特征提取圖（實驗仿真結果圖）.jpg

?????文件???????1187??2012-05-14?21:53??LBP（修改版）\main.asv

?????文件???????1187??2012-05-14?21:53??LBP（修改版）\main.m

?????文件????????288??2012-05-14?21:50??LBP（修改版）\read.txt

?????目錄??????????0??2012-05-14?21:54??LBP（修改版）

-----------?---------??----------?-----??----

????????????????70347????????????????????13