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資源簡(jiǎn)介

SSDA序貫相似性檢測(cè)方法對(duì)圖像進(jìn)行模板匹配。從源圖像中取小圖,再到源圖像中找到小圖所處的位置。

資源截圖

代碼片段和文件信息

%?讀入兩幅圖片
S=imread([‘C:\Documents?and?Settings\xhd\桌面\right.bmp‘]);%原圖像
T=imread([‘C:\Documents?and?Settings\xhd\桌面\eye1.bmp‘]);%模板圖像
S=double(S);
T=double(T);
figure;imshow(uint8(T))
%求取模板圖片的灰度平均值TAverage
T1=0;
for?I=1:THeight
????for??J=1:TWidth
????????T1=T1+T(IJ);
????end;
end;
TAverage=T1/(THeight*TWidth);

R=zeros(256-THeight+1256-TWidth+1);Tk=1;%閾值Tk和累計(jì)次數(shù)矩陣R

%?從左上角開始運(yùn)算
for?i=1:(256-THeight+1)
????for?j=1:(256-TWidth+1)
????????
%?求子圖片的平均值SijAverage
????????Sij=S(i:(i+THeight-1)j:(j+TWidth-1));
????????SijAverage=0;
????????for?m=1:THeight
????????????for?n=1:TWidth
????????????????SijAverage=(SijAverage+Sij(mn));
????????????end;
????????end;
????????SijAverage=SijAverage/(THeight*TWidth);
????????
%?隨機(jī)選點(diǎn),求誤差e和累積誤差Sum
????????Sum=0;
????????while

?屬性????????????大小?????日期????時(shí)間???名稱
-----------?---------??----------?-----??----

?????文件???????1610??2010-07-22?10:21??SSDA\Untitled.m

?????文件????????343??2010-07-22?10:20??SSDA\Untitled1.m

?????目錄??????????0??2010-08-19?09:12??SSDA

-----------?---------??----------?-----??----

?????????????????1953????????????????????3


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