%available:計算可用圖像塊
%availabler和availablec為隱藏塊首地址的行標和列標，image為載體圖像，woeblk為用到的圖像塊數msgblk為嵌入信息的圖像塊數unblk為不可用的圖像塊數
function?[availableravailablecimagewoeblkmsgblkdblkunblk]?=?available（msgcountrowcolmnimageR1R0lumdarandrrandc?）;
msgquan=1;
unable=0;
difficult=0;
for?blockquan=1:m*n
????p1bi=computep1bi（row（blockquan）col（blockquan）image）;
????if?p1bi>=R1+3*lumda?||p1bi<=R0-3*lumda?
????????row（blockquan）=-1;%標記為無效塊
????????col（blockquan）=-1;
????????unable=unable+1;
????????msgquan=msgquan-1;
????elseif?msg（msgquan1）==1?&&?p1bi<=R0
????????image=editp1bi（row（blockquan）col（blockquan）image13*lumdarandrrandc）;
????????row（blockquan）=-1;
????????col（blockquan）=-1;
????????difficult=difficult+1;
????????msgquan=msgquan-1;
????elseif?msg（msgquan1）==0?&&?p1bi>=R1
????????image=editp1bi（row（blockquan）col（blockquan）image03*lumdarandrrandc）;
????????row（blockquan）=-1;
????????col（blockquan）=-1;
????????difficult=difficult+1;
????????msgquan=m

?屬性????????????大小?????日期????時間???名稱
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?????文件???????2001??2018-11-07?22:04??二值圖像隱寫\available.m

?????文件????????968??2018-11-02?16:11??二值圖像隱寫\binaryextract.m

?????文件???????2377??2018-11-07?22:05??二值圖像隱寫\binaryhide.m

?????文件????????279??2018-10-26?10:17??二值圖像隱寫\computep1bi.m

?????文件????????895??2018-10-26?10:47??二值圖像隱寫\editp1bi.m

?????文件?????????17??2018-11-02?16:17??二值圖像隱寫\extractmsg.txt

?????文件??????18346??2018-10-25?21:24??二值圖像隱寫\former.jpg

?????文件????????709??2018-11-02?15:54??二值圖像隱寫\hashreplacement.m

?????文件??????18769??2018-11-07?22:12??二值圖像隱寫\later.jpg

?????文件????????140??2018-10-25?21:19??二值圖像隱寫\md.m

?????文件???????4643??2018-10-26?10:07??二值圖像隱寫\md5.m

?????文件????????135??2018-10-26?09:31??二值圖像隱寫\md52num.m

?????文件??????????6??2018-11-02?16:18??二值圖像隱寫\msg.txt

?????文件????????555??2018-10-26?11:14??二值圖像隱寫\tablec.m

?????目錄??????????0??2018-11-08?00:05??二值圖像隱寫

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????????????????49840????????????????????15