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    發(fā)布日期: 2021-03-27
  • 語言: Matlab
  • 標簽: matlab??

資源簡介


數(shù)字信號處理 丁玉美著 第四章答案 希望大家會有用處

資源截圖

代碼片段和文件信息

close?all
clear
clc
%%%%%%%%%%%%%%%%%%%????輸入信號???%%%%%%%%%%%%%%%%%%%
N?=?512;fs=100;IP=80;;
f1?=?0.2*fs;f2?=?0.3*fs;
fan1?=?0;?fan2?=?0;
t?=?0:1./fs:(N-1)/fs;
x?=?sin(2*pi*f1*t?+?fan1)?+?sin(2*pi*f2*t?+?fan2);
y?=?awgn(x10);
plot(tx);title(‘無噪聲原始信號‘);
figure;plot(ty);title(‘加噪輸入信號‘);
%%%%%%%%%%%%%%%%%%%???周期圖法求功率譜?%%%%%%%%%%%%%%%%
y_z?=?fftshift(abs(fft(yN)).^2/N);
df=fs./N;
f=(0:df:df*(N-1))-fs./2;
figure;plot(f10*log10(y_z));title(‘周期圖法(dB)譜估計‘);

%%%%%%%%%%%%%%%%%%%%%%%?p=0?????%%%%%%%%%%%%%%%%%%%%%%
ef=zeros(IPN);
eb=zeros(IPN);
ef(1:)=y;??????%?ef(0:)
eb(1:)=y;??????%?eb(0:)
row(1)=y*y‘/N;??%ρ=row
k(1)=0;?????????%k(0)
%%%%%%%%%%%%%計算a(pi)?power(p)?p=1?2?3?...IP%%%%%%%%%%?
a=zeros(IP+1IP+1);
power(1)=row(1);
for?p=2:IP+1
????numerator=0;
????denominator=0;
????for?n=p:N
????numerator=?numerator+?(-2)*ef(p-1n)*eb(p-1n-1);
????denominator=denominator+(ef(p-1n))^2+(eb(p-1n-1))^2;
????end
????k(p)=numerator./(denominator+0.0001);??

?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----

?????文件???????1732??2006-11-29?13:57??功率普估計\burg.m

?????文件???????1332??2006-11-10?09:21??功率普估計\levenson.m

?????文件????????361??2006-11-10?00:05??功率普估計\zhouqitu.m

?????目錄??????????0??2009-06-07?19:36??功率普估計

-----------?---------??----------?-----??----

?????????????????3425????????????????????4


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