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資源簡介

四元數(shù)分解的點云配準,輸入點云的源坐標和目標坐標,計算期望的旋轉矩陣和平移向量。

資源截圖

代碼片段和文件信息

function?H?=?Quater_Registration(Source?Target)
%?function?Quater_Registration?is?used?to?calculate?the?transformation?from?CYS?1?to?CYS?2?
%?Source?contains?points?in?CYS1?which?need?to?be?transformed?and?Target?contains?points?in?final?CYS2.
%?Target?=?H?*?Source;
%?Target?=?R?*?Source?+?T;

m?=?size(Source1);
ASource?=?[];
BTarget?=?[];
for?i=1:m-1
????ASource(i:)?=?Source(i:)?-?Source(i+1:);
end
for?i=1:m-1
????BTarget(i:)?=?Target(i:)?-?Target(i+1:);
end

A=[];
B=[];
for?k=1:i
????v=ASource(k:)+BTarget(k:);
????C?=?[?0???-v(3)?v(2);
??????v(3)?0???-v(1);
?????-v(2)?v(1)??0???];
????A?=?vertcat(AC);
????B?=?vertcat(B(ASource(k:)-BTarget(k:))‘);
end

X?=?inv(A‘*A)*A‘*B;?
K?=?X/norm(X);??????%?K?is?the?rotation?vector;
Theta?=?2*atan(max(X)/max(K));??????%?in?radian

kx=K(1);
ky=K(2);
kz=K(3);
t?=?Theta;??????%?in?radian

ct=?cos(t);
st=?sin(t);
vt=?1-cos(t);

%?input?rotation?matrix?R
R?=?[kx^2*vt+ct?????kx*ky*vt-kz*st?kx*kz*vt+ky*st;
??????kx*ky*vt+kz*st?ky^2*vt+ct?????ky*kz*vt-kx*st;
??????kx*kz*vt-ky*st?ky*kz*vt+kx*st?kz^2*vt+ct];
T?=?mean((Target‘?-?R?*?Source‘)2);
T_Q?=?vertcat(horzcat(RT)[0?0?0?1]);

H?=?T_Q;

?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----

?????文件???????1200??2014-05-29?17:35??Quater_Registration.m

-----------?---------??----------?-----??----

?????????????????1200????????????????????1


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