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    文件類型: .rar
    金幣: 1
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    發(fā)布日期: 2021-04-17
  • 語言: Matlab
  • 標簽: sm??ml??qam??

資源簡介

4 QAM Spatial modulation with maximum likehood detection

資源截圖

代碼片段和文件信息

clc
clear?all;
N=3*10^5;??????????????????????%number?of?symbol
symbol_set=[1+1i;1-1i;1i-1;1i-1i]/sqrt(2);???%set?of?symbol?to?be?transmitted
symbolset_size=4;
symbol_size=N/3;
Eb_No_Db=(0:25);
nTx=2;??????????????????????????????%?number?of?transmitting?antenna
nRx=2;??????????????????????????????%?number?of?receiving?antenna
antennabits=[0;1];
Sym_to_bit=[0?0;0?1;1?0;1?1];

i=randi([0?1]1N)?;????%?generating?stream?of?bits

x=vec2mat(i3);??????????%?grouping?generated?bits?into?3

s=kron(symbol_setones(nRx1));???%?grouping?symbols?into?matrix
s=repmat(s[1?nTx]);
xTransmit=zeros(symbol_sizenTx);?????????????????????????????????????????????????????????????
xDemod=zeros(symbol_size3);??????????????????????????????????????????????????????????????????

antenna_symbol=zeros(N/31);????
antenna_symbol(:1)=x(:1)+1;???????%?
antenna_symbol(:2)=symbol_set(bi2de(x(:2:3)‘left-msb‘)+1)?;???%Modulate

for?ii=1:length(Eb_No_Db)
????
????for?jj=1:symbol_size
???????
????????h=1/sqrt(2)*(randn(nRxnTx))+?1i*(randn(nRxnTx));????%?rayleigh?channel
????????
????????n=1/sqrt(2)*(randn(nRx1))+1i*(randn(nRx1));????????????%?noise
????????
????H=kron(ones(symbolset_size1)h);??????
??????sD=?H.*s;
??????
????????????xTransmit(jjantenna_symbol(jj1))?=antenna_symbol(jj2)?;?????????????%?Assign?Symbol?and?Antenna?Index
????????????xTransmit2=kron(xTransmit(jj:)ones(nRx1));
????????????
????????????y?=?sum(xTransmit2.*h2)?+10^(-Eb_No_Db(ii)/20)*n;
????????????
????????????y2=kron(ones(symbolset_size1)y);??????????????????????????????????????????????????%?Copy?for?Symbol?set
????????????y2=repmat(y21nRx);????????????????????????????????????????????????????????????%?Copy?for?Antenna
????????????y2=abs(y2-sD);

????????????z=zeros(symbolset_sizenTx);
????????????z(1:)=abs(sum(y2(1:2:)1));
????????????z(2:)=abs(sum(y2(3:4:)1));
????????????z(3:)=abs(sum(y2(5:6:)1));
????????????z(4:)=abs(sum(y2(7:8:)1));
????????????[v?r]=min(z);
????????????[v?c]=min(v);
????????????xDemod(jj1)=antennabits(c);
????????????
????????????xDemod(jj2:3)=Sym_to_bit(r(c):);
??????
????end
????
????nErr(ii)=?size(find(i-reshape(xDemod‘1[]))2);
end
simBER?=?nErr/N;


close?all
figure
semilogy(Eb_No_DbsimBER‘m.-‘‘linewidth‘2);
axis([0?20?10^-5?1])
grid?on
legend(‘Sim?4QAM‘);
xlabel(‘Eb/No?dB‘)
ylabel(‘Bit?Error?Rate‘)
title(‘Bit?Error?Prob?4QAM?2x2?(3?Bit)?with?SM?in?Rayleigh?Fading‘)


?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----

?????文件???????2498??2014-05-17?01:18??SM_4QAM_ML.m

-----------?---------??----------?-----??----

?????????????????2498????????????????????1


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