資源簡介
借助(非線性)孿生支持向量機,來解決二分類問題。
代碼片段和文件信息
function?[?]?=?ker_contour(kerXv)
%?繪制contour
xaxis?=?1;
yaxis?=?2;
aspect?=?0;
mag?=?0.1;
input?=?zeros(1size(X2));%?一行兩列,元素全為0
[mn]=size(v);
m=max(mn);
alpha=v(1:m-1);
bias=v(m);
d=floor(m/2);
xmin?=?min(X(:xaxis));?xmax?=?max(X(:xaxis));?
????ymin?=?min(X(:yaxis));ymax?=?max(X(:yaxis));?
????xa?=?(xmax?-?xmin);?ya?=?(ymax?-?ymin);
????if?(~aspect)
???????if?(0.75*abs(xa)???????????offadd?=?0.5*(ya*4/3?-?xa);
??????????xmin?=?xmin?-?offadd?-?mag*0.5*ya;?xmax?=?xmax?+?offadd?+?mag*0.5*ya;
??????????ymin?=?ymin?-?mag*0.5*ya;?ymax?=?ymax?+?mag*0.5*ya;
???????else
??????????offadd?=?0.5*(xa*3/4?-?ya);
??????????xmin?=?xmin?-?mag*0.5*xa;?xmax?=?xmax?+?mag*0.5*xa;
??????????ymin?=?ymin?-?offadd?-?mag*0.5*xa;?ymax?=?ymax?+?offadd?+?mag*0.5*xa;
???????end
????else
???????xmin?=?xmin?-?mag*0.5*xa;?xmax?=?xmax?+?mag*0.5*xa;
???????ymin?=?ymin?-?mag*0.5*ya;ymax?=?ymax?+?mag*0.5*ya;
????end
????
????set(gca‘XLim‘[xmin?xmax]‘YLim‘[ymin?ymax]);??
????X=X‘;
????%??繪制函數(shù)值
????[xy]?=?meshgrid(xmin:(xmax-xmin)/d:xmaxymin:(ymax-ymin)/d:ymax);?
????z?=?bias*ones(size(x));
????for?x1?=?1?:?size(x1)
??????for?y1?=?1?:?size(x2)
????????input(xaxis)?=?x(x1y1);?input(yaxis)?=?y(x1y1);
????????z(x1y1)?=?z(x1y1)+ker_Gaussian(inputXker)*alpha;???????
??????end
????end
???
??????shading?interp
????%??繪制康托圖的邊界
????contour(xyz[00]‘k‘);?????%?繪制值為零的等高線?
????hold?on
????contour(xyz[-1?-1]‘k:‘)???%?繪制值為-1的等高線
????contour(xyz[1?1]‘k:‘)?????%?繪制值為1的等高線
end
?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????文件???????5748??2012-09-03?18:32??ker_Main.m
?????文件???????1535??2012-05-21?18:05??N_n.mat
?????文件???????1548??2012-05-21?18:05??N_p.mat
?????文件???????1253??2012-05-31?20:13??twinsvm_ker_train.m
?????文件???????1597??2012-06-05?22:10??ker_contour.m
?????文件????????234??2012-05-24?18:36??ker_Gaussian.m
-----------?---------??----------?-----??----
????????????????11915????????????????????6
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