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資源簡介

很好的mATLAB代碼,利用最大交叉熵,確定迭代次數,完成pcnn脈沖耦合神經網絡的圖像分割,效果很好

資源截圖

代碼片段和文件信息

clc
clear?all
close?all
%%
%參數設置
np?=?50;%迭代次數
alpha_F?=?0.5;
alpha_L?=?0.1;
alpha_T?=?0.5;
vF?=?0.5;
vL?=?1.0;
vT?=?95.4;%對于5用155;對于4用120;對于2\3用110
M?=?[0.5?1?0.5;?1?0?1;?0.5?1?0.5];
%%
im=imread(‘u3.jpg‘);
if?length(size(im))?==?3
????im?=?rgb2gray(im);
end
im=imresize(im0.5);
figureimshow(uint8(im));
title(‘原始圖像‘);

%%
[p?q]=size(im);
New?=?zeros(p?q);
%%
beta?=?0.3;
deta?=?3;
%%?
L?=?zeros(p?q);
T?=?vT?*?ones(p?q);
Y?=?zeros(p?q?np);
Y0?=?zeros(p?q);
F?=?double(im);
H?=?zeros(1?np);
R?=?zeros(p?q);
Res?=?zeros(p?q);
for?i?=?1:np
????L?=?exp(-alpha_L)?*?L?+?conv2(Y(:?:?i)?M?‘same‘);
????U?=?F?.*?(1?+?beta?*?L);
????Y(:?:?i?+?1)?=?im2double(U?>?T);
????T?=?T?-?deta?+?vT?*?Y(:?:?i?+?1);
????P1?=?sum(sum(Y(:?:?i?+?1)))?/?(p?*?q);
????P0?=?1?-?P1;
????H(i)?=?-P1?*?log10(P1)?-?P0?*?log10(P0);
end
%%
n_best?=?find(H?==?max(H));
for?n?=?1:n_best
????R?=?R?+?Y(:?:?n);
end
for?i=1:p
????for?j=1:q
????????if?R(ij)>1
????????????Res(ij)=1;
????????end
????end
end
%%

Pa_AreaMin?=?1024;
BwImgArea??=?bwareaopen(Res?Pa_AreaMin??8);
BwImgArea=double(BwImgArea);

for?i=1:p
????for?j=1:q
????????if?Res(ij)==BwImgArea(ij)
????????????out(ij)=0;
????????else?out(ij)=1;
????????end
????end
end

out=out*255;

figure?imshow(uint8(out));
title(‘PCNN分割效果‘);




?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----

?????文件???????1399??2011-12-15?14:56??codeandpaper\pcnn_seg.m

?????文件?????408597??2012-09-03?23:07??codeandpaper\一種基于交叉熵的改進型PCNN圖像自動分割新方法.caj

?????目錄??????????0??2012-09-03?23:06??codeandpaper

-----------?---------??----------?-----??----

???????????????409996????????????????????3


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