資源簡(jiǎn)介
有詳細(xì)的介紹,如何使用slm降低峰值平均功率比
代碼片段和文件信息
%?SLM--PAPR?Simulation
clear?all;?clc;?close?all;
K?=?128;????????????????????????????????????????????????????????????????????%?SIZE?OF?FFT?
N?=?6;??????????????????????????????????????????????????????????????????????%?NUMBER?OF?SELECTIONS
QPSK_Set??=?[1?-1?i?-i];
Phase_Set?=?[1?-1];
MAX_SYMBOLS??=?1e4;
PAPR_Orignal?=?zeros(1MAX_SYMBOLS);
PAPR_SLM?????=?zeros(3MAX_SYMBOLS);
X?????=?zeros(NK);
Index?=?zeros(NK);
for?nSymbol=1:MAX_SYMBOLS
????Index(1:)???=?randint(1Klength(QPSK_Set))+1;
????Index(2:N:)?=?randint(N-1Klength(Phase_Set))+1;
????
????X(1:)?=?QPSK_Set(Index(1:));??????????????????????????????????????????%?Orignal?Frequency?domain?signal
????Phase_Rot?=?Phase_Set(Index(2:N:));
????X(2:N:)?=?repmat(X(1:)N-11).*Phase_Rot;?????????????????????????????%?Phase?roated?Frequency?domain?signal
????
????x?=?ifft(X[]2);???????????????
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