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    發(fā)布日期: 2021-05-22
  • 語(yǔ)言: 其他
  • 標(biāo)簽: 濾波??

資源簡(jiǎn)介

基于雙因子抗差權(quán)的KALMAN濾波模型研究,里面有具體文章供參考,謝謝原作者!

資源截圖

代碼片段和文件信息

function??[X_estCovX_est]?=?bifactorLS(LAQl)

????%?INPUT?:?L?observation?vector;
????%?????????A?design?matrix?;
????%?????????Ql?covariance?matrix?of?L;
????%?OUTPUT:?X_est?state?vector;
????%?????????covariance?matrix?of?X_est;

P=inv(Ql);
X=inv(A‘*P*A)*A‘*P*L;
V=A*X?-?L;

%?????????%?K0=2.0-3.0;
%?????????%?K1=4.5-8.5;
????????????K0=2.0;
????????????K1=2.5;
%?while?((norm(V1)>tol)&(iter
??????????standardedV=abs(V./std(V));
??????????[mm]=size(P);
??????????r?=?zeros(1m);
%?start?calculate?reduction?factors
?????????????????????????????????for?ii=1:m
???????????????????????????????????????if?standardedV(ii)?<=?K0
????????????????????????????????????????????????r(ii)?=?1;
???????????????????????????????????????????elseif?(standardedV(ii)?>=?K0)?&?(standardedV(ii)?<=?K1)
????????????????????????????????????????????????r(ii)=?K0/abs(standardedV(ii))*((K1-abs(standardedV(ii)))/(K1-K0));
???????????????????????????????????????????else
????????????????????????????????????????????????r(ii)?=?0;
???????????????????????????????????????end?
?????????????????????????????????end
%?start?calculate?equivalent?weight?matrix?eqviP
????????????rij?=?zeros(mm);
????????????????????????????????for?ii?=?1:m
????????????????????????????????????for?jj?=?1:m
????????????????????????????????????????rij(iijj)?=?sqrt(r(ii)*r(jj));
????????????????????????????????????????eqviP(iijj)?=?rij(iijj)*P(iijj);
????????????????????????????????????end
????????????????????????????????end?
????????????????????????????????
%?end
?%?estimating?with?equival?weight?
X_est?=?inv(A‘*eqviP*A)*A‘*eqviP*L;
[nm]=size(A);
deg_free=n-m;
sigma?=?sqrt((V‘*eqviP*V)/(n-m));
%?posteriorcovariance?matrix
CovX_est?=?inv(A‘*eqviP*A)*sigma^2;




?屬性????????????大小?????日期????時(shí)間???名稱(chēng)
-----------?---------??----------?-----??----

?????文件???????1744??2009-06-24?21:40??bifactorRobustkalman\bifactorLS.m

?????文件???????3466??2009-06-24?22:12??bifactorRobustkalman\mainpro.M

?????文件??????28001??2009-05-24?11:19??bifactorRobustkalman\Roverpsedo.mat

?????文件???????1166??2009-06-24?21:40??bifactorRobustkalman\W_Robust_Kalman.m

?????文件?????297984??2009-06-25?18:53??bifactorRobustkalman\基于雙因子抗差權(quán)的KALMAN濾波模型研究.doc

?????目錄??????????0??2009-12-21?09:02??bifactorRobustkalman

-----------?---------??----------?-----??----

???????????????332361????????????????????6


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