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大小: 4KB文件類型: .rar金幣: 2下載: 0 次發(fā)布日期: 2021-06-09
- 語言: 其他
- 標(biāo)簽:
資源簡介
進制轉(zhuǎn)換,可供新手參考,函數(shù)怎么調(diào)用,回調(diào)函數(shù)等,思路清晰,代碼簡單。

代碼片段和文件信息
#include?
using?namespace?std;
string?tostring(int?a)
{
????switch?(a)?{
????case?10:
????????return?“a“;
????????break;
????case?11:
????????return?“b“;
????????break;
????case?12:
????????return?“c“;
????????break;
????case?13:
????????return?“d“;
????????break;
????case?14:
????????return?“e“;
????????break;
????case?15:
????????return?“f“;
????case?0:
????????return?“0“;
????????break;
????case?1:
????????return?“1“;
????????break;
????case?2:
????????return?“2“;
????????break;
????case?3:
????????return?“3“;
????????break;
????case?4:
????????return?“4“;
????????break;
????case?5:
????????return?“5“;
????case?6:
????????return?“6“;
????????break;
????case?7:
????????return?“7“;
????????break;
????case?8:
????????return?“8“;
????????break;
????case?9:
????????return?“9“;
????????break;
????default:
????????break;
????}
}
int?main()
{
????cout?<“input?num?tohex:?“?<????int?num;
????cin?>>?num;
????string?b;
????while(num?>?0)
????{
????????b.insert(0tostring(num?%?16));
????????num?=?num/16;
????}
????cout?<}
?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????文件???????7008??2015-08-06?22:07??tohex\deployment.pri
?????文件???????1134??2015-08-07?01:05??tohex\main.cpp
?????文件????????143??2015-08-06?22:07??tohex\tohex.pro
?????文件??????18619??2015-08-08?01:10??tohex\tohex.pro.user
?????目錄??????????0??2015-08-08?01:10??tohex
-----------?---------??----------?-----??----
????????????????26904????????????????????5
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