資源簡介
通過開發板msp430G2553調試成功的點陣程序

代碼片段和文件信息
#include
#define?uchar?unsigned?char
#define?uint?unsigned?int
void?delay(char?b)
{?uchar?a;
??for(;b>0;b--)
????for(a=0;a<200;a++); ?
?}
void?main()
?{?uchar?w;
???uint ijkm;
???uchar??tab[]={?0x180x240x240x240x240x240x240x18
??????????????????0x000x660xff0xff0x7e0x3c0x180x00
??0x000x040x140x540x540x540x140x04
?};
???P1DIR=0XFF;
???P2SEL=0XFF;
???P2DIR=0X00;
???
?while(1)
?{for(k=0;k<3;k++)
???{for(m=0;m<20;m++)
????{w=0x01;
?j=k*8;
?for(i=0;i<8;i++)
?{P1OUT=w;
??P2OUT=~tab[j];
??delay(20);
??w<<=1;
??j++;
??}
?}
}?
???}
??}??
?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????文件??????15440??2014-07-29?11:24??基于2553的點陣\Debug\Exe\tao.d43
?????文件?????234596??2014-07-29?11:24??基于2553的點陣\Debug\Obj\main.pbi
?????文件???????9713??2014-07-29?11:24??基于2553的點陣\Debug\Obj\main.pbi.cout
?????文件???????7474??2014-07-29?11:24??基于2553的點陣\Debug\Obj\main.r43
?????文件?????237052??2014-07-29?11:27??基于2553的點陣\Debug\Obj\tao.pbd
?????文件?????237052??2014-07-29?11:27??基于2553的點陣\Debug\Obj\tao.pbd.browse
?????文件????????639??2014-07-29?11:24??基于2553的點陣\main.c
?????文件??????????0??2014-07-25?19:11??基于2553的點陣\path.txt
?????文件???????1456??2014-07-29?11:27??基于2553的點陣\settings\tao.cspy.bat
?????文件???????6847??2014-07-29?14:36??基于2553的點陣\settings\tao.dbgdt
?????文件???????1356??2014-07-29?14:36??基于2553的點陣\settings\tao.dni
?????文件???????3033??2014-07-29?14:36??基于2553的點陣\settings\TAO.wsdt
?????文件???????1951??2014-07-29?14:36??基于2553的點陣\tao.dep
?????文件??????20422??2014-07-25?19:01??基于2553的點陣\tao.ewd
?????文件??????52284??2014-07-25?19:01??基于2553的點陣\tao.ewp
?????文件????????157??2014-07-25?19:01??基于2553的點陣\TAO.eww
?????文件?????????25??2014-07-29?14:36??基于2553的點陣\taoCustomSfr.sfr
?????目錄??????????0??2014-07-25?21:02??基于2553的點陣\Debug\Exe
?????目錄??????????0??2014-07-25?18:58??基于2553的點陣\Debug\List
?????目錄??????????0??2014-07-29?11:27??基于2553的點陣\Debug\Obj
?????目錄??????????0??2014-07-25?21:02??基于2553的點陣\Debug
?????目錄??????????0??2014-07-25?21:02??基于2553的點陣\settings
?????目錄??????????0??2014-07-29?11:24??基于2553的點陣
-----------?---------??----------?-----??----
???????????????829497????????????????????23
- 上一篇:簡單計時器
- 下一篇:單片機 實現多路任意延時的一種方法
評論
共有 條評論