function?ICAedS?=?fastica_3_1（MixedS）
%%%%%%%%%%%%%%%%%%%%%%%%%%??標(biāo)準(zhǔn)化??%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
MixedS_mean=zeros（31）;
for?i=1:3
????MixedS_mean（i）=mean（MixedS（i:））;
end????????????????????????????????????????%?計(jì)算MixedS的均值

for?i=1:3
????for?j=1:size（MixedS2）
????????MixedS（ij）=MixedS（ij）-MixedS_mean（i）;
????end
end

%%%%%%%%%%%%%%%%%%%%%%%%%%%??白化??%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

MixedS_cov=cov（MixedS‘）;????????????????????%?cov為求協(xié)方差的函數(shù)
[ED]=eig（MixedS_cov）;??????????????????????%?對(duì)信號(hào)矩陣的協(xié)方差函數(shù)進(jìn)行特征值分解
Q=inv（sqrt（D））*（E）‘;????????????????????????%?Q為白化矩陣
MixedS_white=Q*MixedS;??????????????????????%?MixedS_white為白化后的信號(hào)矩陣
IsI=cov（MixedS_white‘）;?????????????????????%?IsI應(yīng)為單位陣????????????

%%%%%%%%%%%%%%%%%%%%%%%%　FASTICA算法??%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
X=MixedS_white;????????????????????????????%?以下算法將對(duì)X進(jìn)行操作
[VariableNumSampleNum]=size（X）;
numofIC=VariableNum;???????????????????????%?在此應(yīng)用中，獨(dú)立元個(gè)數(shù)等于變量個(gè)數(shù)
B=zeros（numofICVariableNum）;??????????????%?初始化列向量w的寄存矩陣B=[b1??b2??...???bd]
for?r=1:numofIC
????i=1;maxIterationsNum=100;???????????????%?設(shè)置最大迭代次數(shù)（即對(duì)于每個(gè)獨(dú)立分量而言迭代均不超過(guò)此次數(shù)）
????k=0;
????b=rand（numofIC1）;??????????????????%?隨機(jī)設(shè)置b初值
????b=b/norm（b）;
????%HHH=b;
????%?對(duì)b標(biāo)準(zhǔn)化?norm（b）:向量元素平方和開(kāi)根號(hào)
????while?i<=maxIterationsNum+1
????????if?i?==?maxIterationsNum???????????%?循環(huán)結(jié)束處理
????????????fprintf（‘\n第%d分量在%d次迭代內(nèi)并不收斂?！?rmaxIterationsNum）;
????????????break;
????????end
????????bOld=b;??????????????????????????
????????a2=1;
????????t=X‘*b;
????????g=t.*exp（-a2*t.^2/2）;
????????dg=（1-a2*t.^2）.*exp（-a2*t.^2/2）;
%?????????b=（（1-u）*t‘*g*b+u*X*g）/SampleNum-mean（dg）*b;
??????????????????????????%?核心公式，參見(jiàn)理論部分公式2.52
????????ava=（X*g）/SampleNum;
????????ave=mean（dg）*b;
????????b=ava-ave;
????????b=b-B*B‘*b;?
????????b=b/norm（b）;
????????b0=b;
????????t2=X‘*b;
????????dg2=（1-a2*t2.^2）.*exp（-a2*t2.^2/2）;
????????ave2=mean（dg2）*bOld;
????????b=2*ava-ave-ave2;
????????b=b-B*B‘*b;????????????????????????%?對(duì)b正交化
????????b=b/norm（b）;?
????????k=k+1;
%?????????abs（abs（b‘*bOld）-1）<1e-9
????????if?abs（abs（b‘*b0）-1）<1e-9
???????????%?jjjj=b;?????????????????????%?如果收斂，則
?????????????B（:r）=b;?????????????????????%?保存所得向量b
?????????????fprintf（‘\n第%d分量在%d次迭代?！?rk）
?????????????break;
?????????????
?????????end
????????i=i+1;????????
????end
%????B（:r）=b;????????????????????????????????%?保存所得向量b
end
%%%%%%%%%%%%%%%%%%%%%%%%%%??ICA計(jì)算的數(shù)據(jù)復(fù)原并構(gòu)圖??%%%%%%%%%%%%%%%%%%%%%%%%%
ICAedS=B‘*MixedS_white;???
end%?計(jì)算ICA后的矩陣

?屬性????????????大小?????日期????時(shí)間???名稱
-----------?---------??----------?-----??----

?????文件???????2753??2018-09-14?09:01??f_3_1\fastica_3_1.m

?????文件???????1782??2018-09-14?09:01??f_3_1\f_3_1.m

?????目錄??????????0??2018-12-26?10:22??f_3_1

-----------?---------??----------?-----??----

?????????????????4535????????????????????3