function?[ang]=angle（mepopfitnesspoppopsizelchromfL）
%	計算量子門旋轉的角度

ang?????????????=?zeros（popsizelchrom）;
deta????????????=?0.2*pi;
for?i=1:popsize
??if??fitness（i）<=f?????????????????????%此時向b的投影方向靠攏
????for?j=1:lchrom
??????s=0;
??????a=pop（ij1）;
??????b=pop（ij2）;
??????if?mepop（ij）==0&L（j）==0&a*b>0????%ok
????????s=-1;
??????end???????????
??????if?mepop（ij）==0&L（j）==0&?a*b<0
????????s=1;
??????end????????????
??????if??mepop（ij）==0&L（j）==0&a==0??
????????s=1;
??????end
??????
??????if?mepop（ij）==0&L（j）==1&a*b>0????%ok
????????s=1;
??????end????????????
??????if???mepop（ij）==0&L（j）==1&a*b<0
????????s=-1;
??????end?????????????
??????if??mepop（ij）==0&L（j）==1&?b==0??
????????s=1;
??????end?
??????
??????if?mepop（ij）==1&L（j）==0&a*b>0????????%ok
????????s=-1;
??????end???????????
??????if?mepop（ij）==1&L（j）==0&?a*b<0
????????s=1;
??????end????????????
??????if??mepop（ij）==1&L（j）==0&a==0??
????????s=1;
??????end
??????
??????if?mepop（ij）==1&L（j）==1&a*b>0????????%ok
????????s=1;
??????end????????????
??????if???mepop（ij）==1&L（j）==1&a*b<0
????????s=-1;
??????end?????????????
??????if??mepop（ij）==1&L（j）==1&?b==0??
????????s=1;
??????end?
??????ang（ij）=deta*s;
????end
??else??????????????????????%?fitness（i）>f?此時向x的投影方向靠攏
????for?j=1:lchrom
??????s=0;
??????a=pop（ij1）;
??????b=pop（ij2）;
??????if?mepop（ij）==0&L（j）==0&a*b>0????%ok
????????s=-1;
??????end???????????
??????if?mepop（ij）==0&L（j）==0&?a*b<0
????????s=1;
??????end????????????
??????if??mepop（ij）==0&L（j）==0&a==0??
????????s=1;???????
??????end
??????
??????if?mepop（ij）==0&L（j）==1&a*b>0????%ok
????????s=-1;
??????end???????????
??????if?mepop（ij）==0&L（j）==1&?a*b<0
????????s=1;
??????end????????????
??????if??mepop（ij）==0&L（j）==1&a==0??
????????s=1;???????
??????end
??????
??????if?mepop（ij）==1&L（j）==0&a*b>0????%ok
????????s=1;
??????end????????????
??????if???mepop（ij）==1&L（j）==0&a*b<0
????????s=-1;
??????end?????????????
??????if??mepop（ij）==1&L（j）==0&?b==0??
????????s=1;
??????end?
??????
??????if??mepop（ij）==1&L（j）==1&?a*b>0??%ok
????????s=1;
??????end?
???????if??mepop（ij）==1&L（j）==1&?a*b<0??
????????s=-1;
??????end?
???????if??mepop（ij）==1&L（j）==1&?b==0??
????????s=1;
??????end?
??????ang（ij）=deta*s;
????end?
??end??
end
?

?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----

?????文件?????526272??2013-04-16?09:40??1_QGA\3_量子進化算法.caj

?????文件???????2388??2013-04-16?09:38??1_QGA\angle.m

?????文件????????688??2013-04-16?09:18??1_QGA\measure.m

?????文件?????????66??2013-04-09?09:37??1_QGA\morlet.m

?????文件???????1187??2013-04-15?20:09??1_QGA\nninit_test.m

?????文件???????1170??2013-04-16?09:29??1_QGA\popFitness.m

?????文件???????1824??2013-04-17?09:20??1_QGA\QGA.m

?????文件????????504??2013-04-16?09:09??1_QGA\QGA_test.m

?????文件?????????46??2013-04-09?09:22??1_QGA\sigmoid.m

?????文件?????380709??2013-02-28?08:28??1_QGA\算法_量子遺傳算法的變尺度混沌優化策略研究.pdf

?????目錄??????????0??2013-04-16?09:30??1_QGA

-----------?---------??----------?-----??----

???????????????914854????????????????????11