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數(shù)學(xué)建模中經(jīng)典問(wèn)題商人過(guò)河問(wèn)題的MATLAB源代碼,絕對(duì)是自己想出來(lái)的算法,比枚舉算法的時(shí)間復(fù)雜度要小得多,算法中運(yùn)用了隊(duì)列作為存儲(chǔ)結(jié)構(gòu),自己感覺(jué)非常的巧妙,前天用C語(yǔ)言實(shí)現(xiàn)后,一直想著用MATLAB實(shí)現(xiàn),現(xiàn)在將同樣算法的MATLAB源代碼提供給大家,希望廣大朋友給我提出意見(jiàn)和建議,Email:liang.wang.hubei@gmail.com,謝謝

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代碼片段和文件信息

function?s=businessman
n=input(‘輸入商人數(shù)目:‘);
nn=input(‘輸入仆人數(shù)目:‘);
nnn=input(‘輸入船的最大容量:‘);
if?nn>n
????n=input(‘輸入商人數(shù)目:‘);
????nn=input(‘輸入仆人數(shù)目:‘);
????nnn=input(‘輸入船的最大容量:‘);
end
k=1;
for?i=0:nnn?%產(chǎn)生出所有的可能過(guò)河的決策
????for?j=0:nnn
????????if?(i+j<=nnn)?&(i+j>0)
????????????d(k1:3)=[ij1];???????%1表示從此岸到彼岸
????????????d(k+11:3)=[-i-j-1];??%-1表示從彼岸到此岸
????????????k=k+2;
????????end
????end
end
k=1;
for?i=n:-1:0????????????%產(chǎn)生安全隊(duì)列
????for?j=nn:-1:0
????????if?((i>=j)?&?((n-i)>=(nn-j)))?|?((i==0)|(i==n))
????????????A(k1:3)=[ij1];???????%1表示此岸安全????
????????????k=k+1;
????????end
????end
end
%隊(duì)列數(shù)據(jù)結(jié)構(gòu),第一列表示商人數(shù),第二列表示仆人數(shù),第三列用于記錄該結(jié)點(diǎn)的上一個(gè)結(jié)點(diǎn),第四列表示船的運(yùn)動(dòng)方向(1表示此岸往彼岸運(yùn)動(dòng),-1表示從彼岸往此岸運(yùn)動(dòng))
sq(11)=n;sq(12)=nn;sq(13)=0;sq(14)=1;????????%初始狀態(tài)
front=1;rear=1;?%隊(duì)列的頭尾指針
while(front<=rear)
????x=sq(front1);
????y=sq(front2);
????flag=0;
????if?(sq(front4)==1)
????????for?v=2:2:size(d1)
????????????i=x+d(v1);
????????????j=y+d(v2);
????????????if?(is_save(Aij)==1)
????????????????rear=rear+1;
????????????????sq(rear1)=i;
????????????????sq(rear2)=j;
????????????????sq(rear3)=front;
????????????????sq(rear4)=-1;
????????????end
????????????if?(i==0?&&?j==0)
????????????????flag=1;
????????????end
????????end
????end
????if?(flag==1)
????????break;
????end
????flag=0;
????if?(sq(front4)==-1)
????????for?v=1:2:size(d1)
????????????i=x+d(v1);
????????????j=y+d(v2);
????????????if?(is_save(Aij)==1)?&?(sq(sq(front3)1)~=i?|?sq(sq(front3)2)~=j)
????????????????rear=rear+1;
????????????????sq(rear1)=i;
????????????????sq(rear2)=j;
????????????????sq(rear3)=front;
????????????????sq(rear4)=1;
????????????end
????????????if?(i==0?&&?j==0)
????????????????flag=1;
????????????end
????????end
????end
????if?(flag==1)
????????break;
????end
????front=front+1;
end
%打印路徑
i=sq(rear3);
k=2;
s(11)=0;s(12)=0;
while(i>0)
????s(k1)=sq(i1);
????s(k2)=sq(i2);
????i=sq(i3);
????k=k+1;
end


?屬性????????????大小?????日期????時(shí)間???名稱(chēng)
-----------?---------??----------?-----??----

?????文件???????2082??2010-08-30?15:40??商人過(guò)河MATLAB\businessman.m

?????文件????????149??2010-08-30?07:05??商人過(guò)河MATLAB\is_save.m

?????目錄??????????0??2010-08-30?15:45??商人過(guò)河MATLAB

-----------?---------??----------?-----??----

?????????????????2231????????????????????3


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